如何获取会话值并分配或显示在标签上 [英] how to get the session value and assign or shown on label

问题描述

如何获取会话值并分配给标签我有以下代码

how to get the value of session and assign to a label me have the following code

private void Login()
    {
        //SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["strcon"].ConnectionString);
        //SqlConnection con = new SqlConnection("Server=192.168.0.110;Database=PRODUCT;User Id=sa;Password=abc@123");
        //con.Open();
        //Response.Write("<script>alert('suc')</script>");
        if (txtUserName.Text == "" & txtPassword.Text == "")
        {
            lblMsg.Text = "User ID and Password is Required!";
            //return;
        }
        else
        {
            con.Open();
            SqlCommand com =
            new SqlCommand(
                "select * from tbl_Login where UserName='" + txtUserName.Text + "' and UserPassword='" + txtPassword.Text + "'"
                , con);
            com.CommandType = CommandType.Text;
            SqlDataReader DR;

            DR = com.ExecuteReader();


            if (DR.Read())
            {
                Session["Name"] = txtUserName.Text.ToString();
                Session["DEPTID"] = txtPassword.Text.ToString();
                if (txtUserName.Text != "admin" & txtPassword.Text != "admin")
                {       //how to show the Session Name on lblUserName            
                    //lblUserName.Text = Session["Name"].ToString();
                    Response.Redirect("AddItems.aspx");
                }
                else
                    Response.Redirect("frmLogin.aspx");
            }
            else
            {
                lblMsg.Text = "Invalid Cridential!";
            }
            con.Close();
        }

    }

    protected void btnLogIn_Click(object sender, EventArgs e)
    {
        try
        {
            Login();
        }
        catch (Exception ex)
        {
            lblMsg.Text = ex.Message;
        }
    }

推荐答案

试试这个。



Label1.Text = Session [Name]。Tostring（）;

Try this.

Label1.Text = Session["Name"].Tostring();

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