如何在给定的十进制数组中获得高次数的重复元素... [英] How to get highet number of time repeated element in an given decimal array...

问题描述

嗨我已经给出了十进制数组的集合

decimal [] data = new decimal [] {1,5,4,8,11,1,2,2,3,3,3我想在上面给出的数组中获得最大数量的重复值

例如在上面的数组元素3中重复了3次，所以输出将是3.我希望通过Linq或Lamda表达来达到这个目的。



类似

Hi I have given set of decimal array
decimal[] data = new decimal[]{1, 5, 4, 8, 11, 1, 2, 2, 3, 3, 3};
I want to get the highest number of repeated value in the above given array
for e.g in above array element 3 has been repeated 3 time so the output would be 3. I want to achieve this by Linq or Lamda expression.

something like

IEnumerable<string> query = data.OrderByDescending(n => n.Count()).Select(n => n).first()

;



提前致谢

;

Thanks in advance

推荐答案

这将为您提供每个值的计数：

This will give you each value with it's count:

var counts = data.GroupBy(x => x).Select(g => new { count = g.Count(), value = g.Key });

所以你可以使用Max方法：

So you can just use the Max method:

int highestCount = data.GroupBy(x => x).Select(g => new { count = g.Count(), value = g.Key }).Max(g => g.count);

甚至：

Or even:

int highestCount = data.GroupBy(x => x).Select(g => g.Count()).Max();

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