在运行时重复在Android浏览 [英] Duplicate Views on Android during Run-time

问题描述

我已经创建了一个活动布局文件。在这个布局我已创建了一个TextView和一个EditText一个LinearLayout中。 现在我想创造更多的LinearLayouts，将外观和包含我原来的LinearLayout，但不同的文本完全相同的看法。我也想运行期间以编程方式做到这一点，因为这些的LinearLayout量将运行之间有所不同。 我读过一些关于inflaters，但我不明白他们足够使用它们。

我想这样的事情，很明显，code是错误的，但希望你明白我想要做的：

 的LinearLayout llMain =（的LinearLayout）findViewById（R.id.mainLayout）;
的LinearLayout llToCopy =（的LinearLayout）findViewById（R.id.linearLayoutToCopy）;
对于（INT球员= 0;玩家LT;大小;球员++）
{
   的LinearLayout llCopy = llToCopy.clone（）;
   TextView的电视=（TextView中）llCopy.getChildAt（0）;
   tv.setText（players.get（播放机）.getName（））;
   llMain.addView（llCopy）;
}
 

解决方案

有几种方法可以做到这一点。
一个快速简便的做法是夸大了新的布局，循环的每次迭代：

  LayoutInflater吹气=（LayoutInflater）getSystemService（Context.LAYOUT_INFLATER_SERVICE）;
的LinearLayout父=（的LinearLayout）inflater.inflate（R.layout.main，NULL）;

的for（int i = 0;我小于10;我++）{
    查看孩子= inflater.inflate（R.layout.child，NULL）;
    TextView的电视=（TextView中）child.findViewById（R.id.text）;
    tv.setText（儿童号+ I）;
    parent.addView（子）;
}

的setContentView（父）;
 

另一个（更优雅）解决方案是创建扩展的LinearLayout一个单独的类：

 公共类ChildView扩展的LinearLayout {

    私人TextView的电视;

    公共ChildView（上下文的背景下）{
        超（上下文）;

        View.inflate（背景下，R.layout.child，这一点）;
        电视=（TextView中）findViewById（R.id.text）;
    }

    公共无效的setText（字符串文本）{
        tv.setText（文本）;
    }
}
 

现在你可以在你的循环每次迭代创建一个 ChildView ，并设置通过的setText（字符串文本）的文本方法：

 的for（int i = 0;我小于10;我++）{
    ChildView孩子=新ChildView（本）;
    child.setText（儿童号+ I）;
    parent.addView（子）;
}
 

I have created a Layout file for an activity. In this layout I have created a LinearLayout with a textview and an edittext. Now I want to create additional LinearLayouts that will look and contain the exact same views that my original LinearLayout, but with different texts. I also want to do it programmatically during run because the amount of these LinearLayout will vary between runs. I've read some about inflaters but I don't understand them enough to use them.

I'm thinking something like this, obviously the code is wrong, but hopefully you understand what I want to do:

LinearLayout llMain = (LinearLayout)findViewById(R.id.mainLayout);
LinearLayout llToCopy = (LinearLayout)findViewById(R.id.linearLayoutToCopy);
for(int player = 0; player < size; player++)
{
   LinearLayout llCopy = llToCopy.clone();
   TextView tv = (TextView)llCopy.getChildAt(0);
   tv.setText(players.get(player).getName());
   llMain.addView(llCopy);
}

解决方案

There are several ways to accomplish this.
A quick and easy approach is to inflate a new layout in every iteration of the loop:

LayoutInflater inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
LinearLayout parent = (LinearLayout) inflater.inflate(R.layout.main, null);

for (int i = 0; i < 10; i++) {
    View child = inflater.inflate(R.layout.child, null);
    TextView tv = (TextView) child.findViewById(R.id.text);
    tv.setText("Child No. " + i);
    parent.addView(child);
}

setContentView(parent);

Another (more elegant) solution is to create a separate class extending LinearLayout:

public class ChildView extends LinearLayout {

    private TextView tv;

    public ChildView(Context context) {
        super(context);

        View.inflate(context, R.layout.child, this);
        tv = (TextView) findViewById(R.id.text);
    }

    public void setText(String text) {
        tv.setText(text);
    }
}

Now you can create a ChildView in every iteration of your loop and set the text via the setText(String text) method:

for (int i = 0; i < 10; i++) {
    ChildView child = new ChildView( this );
    child.setText("Child No. " + i);
    parent.addView(child);
}

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