当值大于2.5时，舍入一个int？ [英] Round up an int when value is more than 2.5?

问题描述

大家好！我在google上搜索了这个，但没有任何帮助我，所以有人知道我如何从例2.5中收集一个值 - > 3.0（带整数）。在我的程序中，我有一个下降率（从老板那里得到一个下降是多么常见），它可以说速率是1：6但实际上如果我计算它，它是1：6.6或者其他什么，那么我想要它反而说1：7但是我怎么能这样做？



我现在正在使用这个：

Hi everyone! I've searched on google for this but nothing has helped me so does anyone know how i can round up a value from example 2.5 -> 3.0 (with integers). In my program i have a drop rate (how common it is to get a drop from a boss) and it can say that the rate is 1:6 but actually if i calculate it, it's 1:6.6 or something, then i want it to say 1:7 instead but how can i do this?

I'm using this right now:

int ratecalculation = dropNumber / (int) total; //dropNumber keeps the value for all my items in the listbox, total is every items that get selected when i search for something
                    rate.Text = "Drop rate: 1:" + decimal.Round(ratecalculation, MidpointRounding.ToEven);

推荐答案

首先你需要做一个真正的除法，而不是整数除法（当分子和分母都是整数时，你做一个整数除法。）

然后你可以应用Round（）函数。

这样：

First you need to do a REAL division, not an integer one (you do an integer division when numerator and denominator both are integers).
Then you can apply the Round() function.
This way:

float ratecalculation = (float)dropNumber / total;
int roundedCalculation = (int)Math.Round(ratecalculation);

希望这会有所帮助。

Hope this helps.

// ***************************************************** round

// http://en.wikipedia.org/wiki/Rounding

static int round ( float parameter )
    {

    return ( ( int ) ( parameter + 0.5F ) );
    }

// ***************************************************** round

// http://en.wikipedia.org/wiki/Rounding

static int round ( double parameter )
    {

    return ( ( int ) ( parameter + 0.5 ) );
    }

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