MIPS循环遍历数组 [英] MIPS looping through an array
问题描述
我是MIPS的新手
我正在尝试开发一个程序，该程序从十字数组中获取输入，将其递增2，存储结果返回寄存器$ v0。哪个将保持递增的值。当程序从数组中遇到值0时程序应该停止。
数组的前9个元素将从1到9开始，第十个元素是一个0.
另一个寄存器也将用于保存所有递增值的总和。
我也不能使用任何伪代码。
这是我到目前为止的代码
。数据
数组：
.word 1
.word 2
.word 3
.word 4
.word 5
.word 6
.word 7
.word 8
.word 9
.word 0
.text
lui $ a0,0x1001 #load address 0x1001000将数组放入寄存器$ a0
jal increment #call程序
增量：
lw $ a2,0（$ a0）#load从寄存器$ a0到$ a2的单词
beq $ a2，$ 0，否则#if word加载为0 goto else
addi $ a2，$ a2,2 #add 2
sw $ a2,0（$ a0）#store结果从$ a2回到$ a0
addi $ a0，$ a0,1 #add 1 to $ a0 to point到数组中的下一个值
添加$ v0，$ a2，$ 0 #add从$ a2到$ v0的结果
addi $ v0，$ 0,1
系统调用
jr $ a0
j增量#jump返回程序
else：
添加$ v1，$ a0，$ 0 #once找到0，将最终金额从$ a0存入$ v1
addi $ v1，$ 0,1 $
系统调用
我觉得逻辑是正确的但代码的语义不足
代码可能看起来有点乱，另外一个我也不确定的是索引，我应该使用另一个寄存器来保存数组的0索引？
如果你无法修复它，那么你可以给我一些指示吗？谢谢
I'm a novice to MIPS
I'm trying to develop a program which takes an input from a ten word array, increments it by two, stores the result back into a register $v0. Which will hold the incremented value. The program should stop when it encounters a value of 0 from the array.
The first 9 elements of the array will start from 1 up to 9, with the tenth being a 0.
Another register will also be used to hold the sum of all incremented values.
I can also not make use of any pseudo code.
This is the code i have so far
.data
array:
.word 1
.word 2
.word 3
.word 4
.word 5
.word 6
.word 7
.word 8
.word 9
.word 0
.text
lui $a0, 0x1001 #load address 0x1001000 of the array into register $a0
jal increment #call the procedure
increment:
lw $a2, 0($a0) #load word from register $a0 into $a2
beq $a2, $zero, else #if word loaded is 0 goto else
addi $a2, $a2, 2 #add two
sw $a2, 0($a0) #store result from $a2 back into $a0
addi $a0, $a0, 1 #add 1 to $a0 to point to the next value in the array
add $v0, $a2, $zero #add the result from $a2 into $v0
addi $v0, $zero, 1
syscall
jr $a0
j increment #jump back to the procedure
else:
add $v1, $a0, $zero #once the 0 is found, store the final sum from $a0 into $v1
addi $v1, $zero, 1
syscall
I feel like the logic is correct but the semantics of the code are lacking
The code may seem like a bit of a mess, another area I'm also unsure about is the index, i'm supposed to use another register to hold the 0 based index of the array?
If you can't fix it, then could you give me some pointers? Thanks
推荐答案
v0。哪个将保持递增的值。当程序从数组中遇到值0时程序应该停止。
数组的前9个元素将从1到9开始，第十个元素是一个0.
另一个寄存器也将用于保存所有递增值的总和。
我也不能使用任何伪代码。
这是我到目前为止的代码
。数据
数组：
.word 1
.word 2
.word 3
.word 4
.word 5
.word 6
.word 7
.word 8
.word 9
.word 0
.text
lui
v0. Which will hold the incremented value. The program should stop when it encounters a value of 0 from the array.
The first 9 elements of the array will start from 1 up to 9, with the tenth being a 0.
Another register will also be used to hold the sum of all incremented values.
I can also not make use of any pseudo code.
This is the code i have so far
.data
array:
.word 1
.word 2
.word 3
.word 4
.word 5
.word 6
.word 7
.word 8
.word 9
.word 0
.text
lui
a0,0x1001 #load地址0x1001000数组到寄存器
a0, 0x1001 #load address 0x1001000 of the array into register
a0
jal increment #call程序
增量：
lw
a0
jal increment #call the procedure
increment:
lw
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