套接字不读取数据 [英] Socket is not reading data

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本文介绍了套接字不读取数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试一个简单的Java程序来发送和接收数据......服务器正在发送数据而客户端收到了......但这会产生Socket异常:连接重置



这是我发送Integer值的服务器端代码...



 尝试 
{
ServerSocket server = new ServerSocket( 9089 );

套接字套接字= server.accept();

OutputStream out = socket.getOutputStream();
out.write( 12 );
out.flush();
System.out.println( Data Sent ....);
Thread.sleep( 5000 );
}
catch (例外e)
{
System.out.println( 服务器错误: + e.toString());
}





这是我的客户端代码,用于接收该Int值...



 尝试 
{
Socket client = new Socket(InetAddress.getLocalHost(), 9089 );
System.out.println( 已连接....);

InputStream in = client.getInputStream();
while (in.available()> 0)
{
System.out.println( 不可用......);
}
System.out.println( 收到: + in。 read());
in.close();
}
catch (例外e)
{
System.out.println( 发件人错误: + e.toString());
}



请帮我解决这个问题....

解决方案

我得到了解决方案...



而不是



  while (in.available()> 0)





我需要做的事情



  while (in.available()== 0)


I am trying a simple Java program to send and receive data... Server is sending the data and Client receives that... But this generates Socket Exception : Connection Reset

This is my Server side code to sent Integer value...

try
    {
        ServerSocket server = new ServerSocket(9089);

        Socket socket = server.accept();

        OutputStream out = socket.getOutputStream();
        out.write(12);
        out.flush();
        System.out.println("Data Sent....");
        Thread.sleep(5000);
    }
    catch(Exception  e)
    {
        System.out.println("Server Error : " + e.toString());
    }



This is my Client side code to receive that Int value...

try
    {
        Socket client = new Socket(InetAddress.getLocalHost(), 9089);
        System.out.println("Connected ....");

        InputStream in = client.getInputStream();
        while(in.available()>0)
        {
            System.out.println("Unavailable...");
        }
        System.out.println("Received : " + in.read() );
        in.close();
    }
    catch(Exception e)
    {
        System.out.println("Sender Error : " + e.toString());
    }


Please help me solving this....

解决方案

I got the solution...

Instead of

while(in.available()>0)



I need to do

while(in.available()==0)


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