如何防止JAXB转义字符串 [英] How to prevent JAXB escaping a string

问题描述

我有一个由XJC生成的对象，名为 Product 。我想将 product.currentPrice（一个字符串）设置为& amp;＃x00A3; 210 其中& amp;＃x00A3; 是货币符号（从系统的其他地方传入）。

I have an object, generated by XJC, called Product. I want to set product.currentPrice (a String) to be £210 where £ is the currency symbol (passed in from elsewhere in the system).

麻烦的是， JAXB正在逃离我的&号，因此它产生& amp; amp;＃x00A3; 210 。我如何使它不这样做？

Trouble is, JAXB is escaping my ampersand, so it produces £210 instead. How do I make it not do this?

推荐答案

默认情况下，JAXB的marshaller实现通常会转义字符。要更改此默认行为，您必须编写一个实现 com.sun.xml.bind.marshaller.CharacterEscapeHandler 接口的类。

By default, the marshaller implementation of the JAXB usually escapes characters. To change this default behavior you will have to Write a class that implements the com.sun.xml.bind.marshaller.CharacterEscapeHandler interface.

在Marshaller中设置该处理程序

set that handler in the Marshaller

CharacterEscapeHandler escapeHandler = NoEscapeHandler.theInstance;
marshaller.setProperty("com.sun.xml.bind.characterEscapeHandler", escapeHandler); 

您可以查看JAXB提供的样本，字符转义样本

You can have a look at samples provided with JAXB, character escaping sample

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