在'image.SetSource（stream）;'处将字节数组转换为位图错误未指定的错误 [英] Converting byte array to bitmap error at 'image.SetSource(stream);' Unspecified error

问题描述

我使用下面的代码将Image转换为Byte数组

 public static byte [] ConvertStringToBytes（string input）
 {
 MemoryStream stream = new的MemoryStream（）; 
 
使用（StreamWriter writer = new StreamWriter（stream））
 {
 writer.Write（input）; 
 writer.Flush（）; 
} 
 
 return stream.ToArray（）; 
} 

现在我想将该字节数组重新转换为Imagebitmap，我在下面使用了代码

 public BitmapImage ByteArraytoBitmap（Byte [] byteArray）
 {
 MemoryStream stream = new MemoryStream（byteArray）; 
 
 byte [] bytes = byteArray as byte []; 
 
 BitmapImage image = new BitmapImage（）; 
 
 image.SetSource（stream）; 
 
返回图片; 
} 

但它在'image.SetSource（stream）;'未指定错误

解决方案

好的......它会的。



但不是从字节数组到图像的转换就是问题，它是另一种方法。



看代码：字符串中有什么？如果是图像数据，则可能因转换为字符串而损坏。但更可能的是，它是一个文件名或类似的，而不是实际的图像数据...



使用调试器，并查看字符串。

I used below code to convert Image to Byte array

public static byte[] ConvertStringToBytes(string input)
        {
            MemoryStream stream = new MemoryStream();

            using (StreamWriter writer = new StreamWriter(stream))
            {
                writer.Write(input);
                writer.Flush();
            }

            return stream.ToArray();
        }

Now I want to re convert that byte array to Imagebitmap, i used below code

public BitmapImage ByteArraytoBitmap(Byte[] byteArray)
        {
            MemoryStream stream = new MemoryStream(byteArray);           

            byte[] bytes = byteArray as byte[];

            BitmapImage image = new BitmapImage();

            image.SetSource(stream);

            return image;
        }

But it gives error at 'image.SetSource(stream);' Unspecified error

解决方案

Well yes... It will.

But it's not the conversion from byte array to image that's the problem, it's the other method.

Look at the code: what is in the string? If it's image data, then it's probably corrupt from being converted to a string. But more likely, it's a file name or similar, rather than actual image data at all...

Use the debugger, and look at the string.

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