机器人：如何获取用户的照片Instagram的？ [英] android: how to get user photos in Instagram?

问题描述

在我的应用我的要求是获取用户的照片，并显示在我的应用程序。

有关，我验证，得到了访问令牌，然后输入用户名密码，而是说明你没有权限打开这个页面。接下来，我怎么能得到用户的个人资料和照片。

我在这里的code是：

 字符串URL =htt​​ps://instagram.com/oauth/authorize？ +RESPONSE_TYPE =记号+
 ＆放大器; redirect_uri =+ CALLBACK_URL +＆放大器;范围=基本的+＆放大器; CLIENT_ID =+ CLIENT_ID;

  的WebView的WebView =（web视图）findViewById（R.id.webview）;

  webview.setWebViewClient（新WebViewClient（）{

        公共无效onPageStarted（web视图查看，字符串URL，位图图标）{
            字符串片段=＃access_token =;
            INT开始= url.indexOf（片段）;
            如果（开始＆gt; -1）{

                //你可以使用accessToken的API调用了。
                串accessToken = url.substring（开始+ fragment.length（），url.length（））;

                Log.v（TAG，OAuth的完整，令牌：[+ accessToken +。）;
                Log.i（TAG，+ accessToken）;
Toast.makeText（ActivityWebView.this，令牌+ accessToken，Toast.LENGTH_SHORT）.show（）;
            }
        }
    }）;

    webview.loadUrl（URL）;
}
 

解决方案

试试这个codeI得到的解决方案，从这样的：

  URL例如=新的URL（https://api.instagram.com/v1/users/self/media/recent?access_token=
                            + accessToken）;

            的URLConnection TC = example.openConnection（）;
            的BufferedReader在=新的BufferedReader（新的InputStreamReader（
                    tc.getInputStream（）））;

            串线;
            而（（行= in.readLine（））！= NULL）{
                JSONObject的OB =新的JSONObject（线）;

                JSONArray对象= ob.getJSONArray（数据）;

                的for（int i = 0; I＆LT; object.length（）;我++）{


                    的JSONObject祚=（的JSONObject）object.get（我）;
                    JSONObject的NJA =（的JSONObject）jo.getJSONObject（照片）;

                    JSONObject的purl3 =（的JSONObject）NJA
                            .getJSONObject（缩略图）;
                    Log.i（TAG，+ purl3.getString（URL））;
                }

            }
        }赶上（MalformedURLException异常E）{

            e.printStackTrace（）;
        }赶上（IOException异常E）{

            e.printStackTrace（）;
        }赶上（JSONException E）{

            e.printStackTrace（）;
        }

    }
 

In my app my requirement is to get the user photos and show in my app.

For that i am authenticate , got access token and enter username password but that shows you don't have permission to open this page. next how can i get user profile and photos.

here my code is:

 String url ="https://instagram.com/oauth/authorize?" +"response_type=token" + 
 "&redirect_uri=" + CALLBACK_URL+"&scope=basic"+"&client_id=" + CLIENT_ID ;

  WebView webview = (WebView)findViewById(R.id.webview);

  webview.setWebViewClient(new WebViewClient() {

        public void onPageStarted(WebView view, String url, Bitmap favicon) {
            String fragment = "#access_token=";
            int start = url.indexOf(fragment);
            if (start > -1) {

                // You can use the accessToken for api calls now.
                String accessToken = url.substring(start + fragment.length(), url.length());

                Log.v(TAG, "OAuth complete, token: [" + accessToken + "].");
                Log.i(TAG, "" +accessToken);
Toast.makeText(ActivityWebView.this, "Token: " + accessToken, Toast.LENGTH_SHORT).show();
            }
        }
    });

    webview.loadUrl(url);
}

解决方案

try this code i got solution from this:

 URL example = new URL("https://api.instagram.com/v1/users/self/media/recent?access_token="
                            + accessToken);

            URLConnection tc = example.openConnection();
            BufferedReader in = new BufferedReader(new InputStreamReader(
                    tc.getInputStream()));

            String line;
            while ((line = in.readLine()) != null) {
                JSONObject ob = new JSONObject(line);

                JSONArray object = ob.getJSONArray("data");

                for (int i = 0; i < object.length(); i++) {


                    JSONObject jo = (JSONObject) object.get(i);
                    JSONObject nja = (JSONObject) jo.getJSONObject(photos);

                    JSONObject purl3 = (JSONObject) nja
                            .getJSONObject("thumbnail");
                    Log.i(TAG, "" + purl3.getString("url"));
                }

            }
        } catch (MalformedURLException e) {

            e.printStackTrace();
        } catch (IOException e) {

            e.printStackTrace();
        } catch (JSONException e) {

            e.printStackTrace();
        }

    }

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