在asp.net中显示多页Tiff图像时出错 [英] getting error while displaying multipage Tiff image in asp.net

问题描述

您好b $ b

任何人都可以帮我在浏览器中显示tiff图像而无需缩略图



我的默认代码.aspx是

Hi
Can anybody help me in displaying a tiff image in the browser without thumbnails

My code in default.aspx is

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Drawing;
using System.Drawing.Imaging;

namespace Documentviewer1
{
    public partial class _Default : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            
            Response.ContentType = "image/tiff";
            string filename = HttpRuntime.AppDomainAppPath + @"\" + Request.QueryString["ImageFileName"];
            new Bitmap(filename).Save(Response.OutputStream,ImageFormat.Jpeg);
 }
    }
}

我正在使用

and I am using

<img src =" ~567892.tif alt width=200 height=200/>

我得到了



在执行当前Web请求期间发生了未处理的异常。请查看堆栈跟踪以获取有关错误及其源自代码的更多信息。



异常详细信息：System.ArgumentException：参数无效。



我缺少什么？



任何人都可以提供帮助







Mary

and I am getting

An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.ArgumentException: Parameter is not valid.

what I am missing?

Can anybody help



Mary

推荐答案

尝试像这样调试



修改你的公司de in（逻辑上没有太大区别）

Try to debug like this

modify your code in such ( not a big difference in logic )

 string appath = HttpRuntime.AppDomainAppPath + @"\";
string imagename = Request.QueryString["ImageFileName"];
 string filename = appath + imagename; // apply break point on this line and check the file name path..
Response.ContentType = "image/tiff";
new Bitmap(filename).Save(Response.OutputStream, ImageFormat.Jpeg);

确保图像存在于该位置。如果图像不可用，则会抛出参数无效错误。

并检查是否从<$收到了值c $ c>查询字符串。 ..

make sure that the image is present in the location. if the image is not available then this will throw the Parameter is not valid error.
and also check that the values is received from the query string...

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