显示图片（从URL）在ImageView的 [英] Display Image(From Url) In ImageView

问题描述

我用这code来显示URL的图像。我的code运行时，并没有给出一个错误，但不显示图像。 任何帮助？

下面是code：

 公共类MainActivity延伸活动{

    ImageView的我;
    字符串IMAGEURL =htt​​p://64.250.238.26:1111/clips/sunsetsofmauisplash.jpg;

    @覆盖
    公共无效的onCreate（包savedInstanceState）{
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.main）;
        尝试 {
            I =（ImageView的）findViewById（R.id.image）;
            点阵位图= BitmapFactory.de codeStream（（InputStream的）新的URL（IMAGEURL）.getContent（））;
            i.setImageBitmap（位）;
        }赶上（MalformedURLException异常E）{

        }赶上（IOException异常E）{

        }

    }
}
 

解决方案

试试这个方法，并记录code会告诉你，如果有被抛出的异常

 公共无效的onCreate（包savedInstanceState）{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;
    尝试 {
       网址URL =新的URL（IMAGEURL）;
       HTTPGET HTT prequest = NULL;

       HTT prequest =新HTTPGET（url.toURI（））;

       HttpClient的HttpClient的=新DefaultHttpClient（）;
       HTT presponse响应=（HTT presponse）httpclient.execute（HTT prequest）;

       HttpEntity实体= response.getEntity（）;
       BufferedHttpEntity b_entity =新BufferedHttpEntity（实体）;
       输入的InputStream = b_entity.getContent（）;

       点阵位图= BitmapFactory.de codeStream（输入）;

        ImageView的I =（ImageView的）findViewById（R.id.image）;
        i.setImageBitmap（位）;
    }赶上（MalformedURLException异常E）{
        Log.e（日志，坏网址，T）;
    }赶上（IOException异常E）{
        Log.e（日志，IO错误，T）;
    }
}
 

更新：

在挖我发现这个修复到去$ C $当时正在记录CR误差

I am using this code to display an image from a URL. My code is run and it does not give an error but the image is not displayed. Any help?

Here is the code:

public class MainActivity extends Activity {

    ImageView i;
    String imageUrl = "http://64.250.238.26:1111/clips/sunsetsofmauisplash.jpg";

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        try {
            i = (ImageView) findViewById(R.id.image);
            Bitmap bitmap = BitmapFactory.decodeStream((InputStream) new URL(imageUrl).getContent());
            i.setImageBitmap(bitmap);
        } catch (MalformedURLException e) {

        } catch (IOException e) {

        }

    }
}

解决方案

try this approach and the logging code will show you if there are any exceptions being thrown

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    try {
       URL url = new URL(imageUrl);
       HttpGet httpRequest = null;

       httpRequest = new HttpGet(url.toURI());

       HttpClient httpclient = new DefaultHttpClient();
       HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);

       HttpEntity entity = response.getEntity();
       BufferedHttpEntity b_entity = new BufferedHttpEntity(entity);
       InputStream input = b_entity.getContent();

       Bitmap bitmap = BitmapFactory.decodeStream(input);

        ImageView i = (ImageView) findViewById(R.id.image);
        i.setImageBitmap(bitmap);
    } catch (MalformedURLException e) {
        Log.e("log", "bad url", t);
    } catch (IOException e) {
        Log.e("log", "io error", t);
    }
}

Update:

After digging I found this Fix to the decoder error that was being logged

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