如何使用pjsua2机器人发送SIP消息 [英] How to send SIP messages using pjsua2 android
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问题描述
我试图用pjsua2发送消息。但它抛出一个异常。请给我建议。
下面是我的code
公共无效sendInstantMessage(字符串buddy_uri){
buddy_uri =SIP:aaaaa@xxx.yyyyyy.zzz;
BuddyConfig CFG =新BuddyConfig();
cfg.setUri(buddy_uri);
cfg.setSubscribe(真正的);
MyBuddy IM =新MyBuddy(CFG);
SendInstantMessageParam PRM =新SendInstantMessageParam();
prm.setContent(这是X,发送消息);
布尔有效= im.isValid();
Log.e(TAG,有效=======+有效);
尝试 {
im.sendInstantMessage(PRM);
}赶上(例外五){
Log.e(TAG,sendInstantMessage ====+ E);
e.printStackTrace();
返回;
}
}
它抛出一个异常,这里是日志
05-27 15:42:40.705:E / SipApi(27611):有效=======假
05-27 15:42:40.706:A /的libc(27611):../src/pjsua-lib/pjsua_$p$ps.c:231:pjsua_buddy_get_info:断言pjsua_buddy_is_valid(buddy_id)失败
解决方案
最后,我用发送短信PJSIP-2.4
解决方案下面是code
/ **发送短信到这个号码
* @参数串号
* @参数字符串msgBody * /
公共无效sendInstantMessage(串号,串msgBody){
字符串sipServer =aaa.ggg.net;
字符串buddy_uri =< SIP:+数字+@+ sipServer +>中;
BuddyConfig执行bcfg =新BuddyConfig();
bCfg.setUri(buddy_uri);
bCfg.setSubscribe(假);
MyBuddy myBuddy =新MyBuddy(与bcfg);
SendInstantMessageParam PRM =新SendInstantMessageParam();
prm.setContent(msgBody);
尝试 {
myBuddy.create(帐户,执行bcfg);
myBuddy.sendInstantMessage(PRM);
myBuddy.delete();
}赶上(例外五){
e.printStackTrace();
返回;
}
}
I am trying to send messages with pjsua2. But it is throwing a exception. Please suggest me.
Here is my code
public void sendInstantMessage(String buddy_uri) {
buddy_uri = "sip:aaaaa@xxx.yyyyyy.zzz";
BuddyConfig cfg = new BuddyConfig();
cfg.setUri(buddy_uri);
cfg.setSubscribe(true);
MyBuddy im = new MyBuddy(cfg);
SendInstantMessageParam prm = new SendInstantMessageParam();
prm.setContent("Hi This is X, sending message");
boolean valid = im.isValid();
Log.e(TAG, "valid ======= "+valid);
try {
im.sendInstantMessage(prm);
} catch (Exception e) {
Log.e(TAG, "sendInstantMessage ==== "+e);
e.printStackTrace();
return;
}
}
It throwing a exception and here is log
05-27 15:42:40.705: E/SipApi(27611): valid ======= false
05-27 15:42:40.706: A/libc(27611): ../src/pjsua-lib/pjsua_pres.c:231: pjsua_buddy_get_info: assertion "pjsua_buddy_is_valid(buddy_id)" failed
解决方案
Finally I got the solution for sending SMS using pjsip-2.4
Here is the code
/**Send message to this number
* @param String number
* @param String msgBody*/
public void sendInstantMessage(String number, String msgBody) {
String sipServer = "aaa.ggg.net";
String buddy_uri = "<sip:" + number + "@" + sipServer + ">";
BuddyConfig bCfg = new BuddyConfig();
bCfg.setUri(buddy_uri);
bCfg.setSubscribe(false);
MyBuddy myBuddy = new MyBuddy(bCfg);
SendInstantMessageParam prm = new SendInstantMessageParam();
prm.setContent(msgBody);
try {
myBuddy.create(account, bCfg);
myBuddy.sendInstantMessage(prm);
myBuddy.delete();
} catch (Exception e) {
e.printStackTrace();
return;
}
}
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