如何添加具有不同行值的新行？ [英] How to add a new row with different row value ?

问题描述

foreach (DataRow row in dt.Rows)
        {
            lstData.Add(new Tablelist() { FileName=csv,  process = row["process"] + "", Event = row["Event"] + "", status = row["status"] + "" });
 
        }
    }
        DataTable dtoutput = new DataTable();
       var columnNames =  lstData.Select(k => k.FileName).Distinct();
       foreach (string columnName in columnNames)       
           dtoutput.Columns.Add(columnName, typeof(string));
       DataRow newrowPassCount = dtoutput.NewRow();
         foreach (string columnName in columnNames) {
            int count = lstData.Where(k=> k.FileName == columnName).Count(k => k.status == "Pass");
            newrowPassCount[columnName] = count; 
        }
         dtoutput.Rows.Add(newrowPassCount);

HI ...目前是最后一个代码dtoutput.Rows.Add（newrowPassCount）;

将使用（newrowpasscount）值创建一行....在第二次循环之后，我需要使用不同的（newrowpasscount）值创建另一行..它现在会做什么它将覆盖上一行..我一直在尝试这个

HI...currently the last code dtoutput.Rows.Add(newrowPassCount);
will create just one row with the (newrowpasscount) value....after second loop I need another row to be created with a different (newrowpasscount) value.. what it does now it will overwrite the previous row..I've been trying this

 foreach (DataRow row in dtoutput.Rows)
{
    dtoutput.Rows.Add(newrowPassCount);
}

但它不起作用...

but it doesn't work...

推荐答案

在下面的代码中将FileName = csv作为静态值并且

In below code u have put FileName=csv as static value and

var columnNames =  lstData.Select(k => k.FileName).Distinct();

总是返回一个值csv。

所以每次将值设置为相同的列名。你需要

保持

always returns one value of "csv".
so every time it set the value to same column name. and u needs to
keep

DataRow newrowPassCount = dtoutput.NewRow();

在foreach循环中



让我知道它是否有帮助。

inside foreach loop

let me know if its help or not.

您需要将 dtoutput.NewRow（）; 移动到foreach循环，以便每次创建的新行都添加到集合中。

You need to move the dtoutput.NewRow(); to the foreach loop so that each time the new row created are added to the collection.

DataTable dtoutput = new DataTable();

// generate the data you want to insert
   DataRow toInsert = ...;

// insert in the desired place
dt.Rows.InsertAt(toInsert, index);

试一试。这可能会有所帮助。

Give it a try.This may help.

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