如何在第二个表的联盟中内部加入第一个表(某些条件的结果) [英] How Do I Inner Join With First Table(Result Of Some Conditions ) In A Union With Second Table

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问题描述

我有两个表FoodList和AlternateFoodList。我想要预约的所有食物和替代食物



预约







AID 日期
1 1-1-2013
2 2-1-2014


FoodLsit



FoodAptID AID FoodID QTY
1 1 1 1
2 1 2 2




AlternateFoodList







FoodAlternateID FoodAptID FoodID QTY
1 1 3 1
2 1 5 2




requiredResult





FoodAlternateID FoodA ptID AID FoodID QTY A_F
1 1 1 1 F
1 1 1 3 1 A
2 1 1 5 1 A




i尝试这样的查询

i have two table FoodList and AlternateFoodList . I want All Food and Alternate Food For a person in an appointment

Appointment



AIDDate
1 1-1-2013
2 2-1-2014

FoodLsit

FoodAptID AIDFoodIDQTY
1 1 1 1
2 1 2 2


AlternateFoodList



FoodAlternateIDFoodAptID FoodIDQTY
11 3 1
21 5 2


requiredResult is


FoodAlternateIDFoodAptID AIDFoodIDQTYA_F
1 1 1 1 F
11 1 3 1 A
21 1 5 1 A


i tried query like this

 select null as 'FoodAlternateID',P. *,"F" as A_F from  FoodAptID P inner join Appointment A on A.AID=P.AID where A.Date ='1-1-2013'
union
(some query where i able to use A.Date ='1-1-2013' in sub table )



PLZ帮助


PLZ help

推荐答案

很抱歉,但你的问题是不清楚还是。



看看例子:

Sorry, but your question is not clear still.

Have a look at example:
DECLARE @Appointment TABLE (AID INT IDENTITY(1,1),  [Date] DATETIME)
INSERT INTO @Appointment ([Date])
VALUES ('2013-01-01'), ('2014-01-02')

DECLARE @FoodLsit TABLE (FoodAptID INT IDENTITY(1,1), AID INT, FoodID INT, QTY INT)
INSERT INTO @FoodLsit (AID, FoodID, QTY)
VALUES(1, 1, 1), (1, 2, 2)

DECLARE @AlternateFoodList TABLE (FoodAlternateID   INT IDENTITY(1,1), FoodAptID INT, FoodID INT, QTY INT)
INSERT INTO @AlternateFoodList (FoodAptID, FoodID, QTY)
VALUES(1, 3, 1), (1, 5, 2)


SELECT AFL.FoodAlternateID , FL.FoodAptID, AFL.FoodID, FL.QTY , A.AID, A.Date
FROM @AlternateFoodList AS AFL INNER JOIN @FoodLsit AS FL ON AFL.FoodAptID = FL.FoodAptID INNER JOIN @Appointment AS A ON FL.AID = A.AID
WHERE A.Date = '2013-01-01'





有关JOIN的更多信息,请参阅: SQL连接的可视化表示 [ ^ ]


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