如何在点击gridview行的asp.net中显示弹出页面 [英] how do I show pop up page in asp.net on click of row of gridview

问题描述

我正在创建一个用于触摸屏的asp.net网站，当用户点击网格视图的一行时，弹出页面必须出现要求用户身份验证，并且必须禁用网格页面。 。

我正在寻找启用此功能的代码..任何人都可以帮助我吗？



aspx页

 <   table  >  
 <   tr  >  
 <   td  >  
 <   asp：GridView     ID   =  GridViewResourceGroup    runat   =  server    CssClass   =  gridTable    EmptyDataText   = 找不到记录   宽度  =  100％    AutoGenerateColumns   =  false     onrowdatabound   = < span class =code-keyword> GridViewResourceGroup_RowDataBound >  
 <   asp：BoundField     DataField   = 代码    HeaderText   = 代码    /  >  
 <   asp：BoundField     DataField   = < span class =code-keyword>工作区    HeaderText   = 工作场所    /  >  
 <   asp：BoundField     DataField   = 描述    HeaderText   = 描述 < span class =code-attribute>   /  >  
 <   / td  >  
 <   / tr  >  
 <   / table  >  

aspx。 cs页

 受保护  void  GridViewResourceGroup_RowDataBound（  object  sender，GridViewRowEventArgs e）
 {
  if （e.Row.RowType == DataControlRowType.DataRow）
 {
 e.Row.Attributes.Add（  onmouseover ，  this.style.backgroundColor ='＃6699FF'）; 
 e.Row.Attributes.Add（  onmouseout，  this.style.backgroundColor ='＃F9F7F7'）; 
} 
} 

解决方案

请尝试谷歌并开始使用。如果您将停在某处，我们一定会帮助您。

另请尝试以下链接：

在ASP.Net中单击GridView行时打开弹出窗口 [ ^ ]

点击gridview linkbutton点击事件打开弹出窗口 [ ^ ]

在gridview行中点击任意位置时打开弹出窗口而不在代码隐藏中回发 [ ^ ]

在gridview链接按钮上打开ajax modelpopup [ ^ ]

打开应用程序页面（.aspx）页面作为弹出窗口时单击GridView上的链接按钮？ [ ^ ]

你可以参考这个链接。



http://www.aspsnippets.com/Articles/Add-Edit-Update-Records-in-GridView-using -Modal-Popup-in-ASP.Net.aspx [ ^ ]



此示例符合您的要求

I am creating a asp.net website to be used on touch screen where when a user clicks on a row of a grid view, pop up page must appear to ask for user authentication and the page of grid must be disable...
I am looking for a code to enable this .. can anyone help me??

aspx page

<table>
  <tr>
    <td> 
      <asp:GridView ID="GridViewResourceGroup" runat="server" CssClass="gridTable" EmptyDataText="No Record Found" Width="100%" AutoGenerateColumns="false" onrowdatabound="GridViewResourceGroup_RowDataBound">
      <asp:BoundField DataField="Code" HeaderText="Code" />
      <asp:BoundField DataField="Workplace" HeaderText="Workplace" />    
      <asp:BoundField DataField="Description" HeaderText="Description" />                            
    </td>
  </tr>
</table>

aspx.cs page

protected void GridViewResourceGroup_RowDataBound(object sender, GridViewRowEventArgs e)
{
  if (e.Row.RowType == DataControlRowType.DataRow)
  {
    e.Row.Attributes.Add("onmouseover", "this.style.backgroundColor='#6699FF'");
    e.Row.Attributes.Add("onmouseout", "this.style.backgroundColor='#F9F7F7'");
  }  
}

解决方案

Please try to google and get started. If you will be stop some where then we will definitely help you.
Also try the following links:
Open Popup window when GridView row is clicked in ASP.Net[^]
open popup on click of gridview linkbutton click event[^]
how to open a popup when click anywhere in gridview row without postback in codebehind[^]
open a ajax modelpopup on gridview link button[^]
Open application page (.aspx) page as a popup when click link button on GridView?[^]

You may refer this link.

http://www.aspsnippets.com/Articles/Add-Edit-Update-Records-in-GridView-using-Modal-Popup-in-ASP.Net.aspx[^]

This example matches with your requirement.

这篇关于如何在点击gridview行的asp.net中显示弹出页面的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！