在Ruby on Rails的针对Android操作系统的API [英] API for Android OS in ruby on rails

问题描述

我需要提供REST风格的API进行开发的Ruby on Rails的带有CRUD功能的Andr​​oid应用程序。我还没有与手机操作系统（安卓/ iphone），与早先的回报率集成。所以，请大家帮我入门。

I need to provide an RESTful api to be developed in ruby on rails with CRUD features for an android app. I haven't worked with mobile phone OS(android/iphone) integration with RoR earlier. So, please help me getting started.

在此先感谢。

推荐答案

您可以将数据为JSON数据包发送到设备，在设备解析JSON数据包和访问数据。你的电话到Web服务应该是一个HTTP调用，例如这是给客户端。

you can send the data as Json packets to the device and in device parse the json packets and access the data. your calls to webservice should be a http call eg this is for the client.

HTTP：？\服务器\方法An Iteraitve \ get_somedata名=事情

http:\server\metnod\get_somedata?name=something

和服务器应该在数据库中查询此参数并发送您的效应初探为JSON。解析JSON，让您的详细信息。

and the server should query the database for this parameter and send you the reponse as Json. parse json and get your details.

String url = "http:\\example.com\mycontroller\get_employee?id=2"

HttpPost httpPostRequest = new HttpPost(url);
    StringEntity se;
    se = new StringEntity(jsonObjSend.toString());


    httpPostRequest.setEntity(se);
    httpPostRequest.setHeader("Authorization", usercredential);
    httpPostRequest.setHeader("Accept", "application/json");
    httpPostRequest.setHeader("Content-type", "application/json");

    long t = System.currentTimeMillis();
    response = (HttpResponse) httpclient.execute(httpPostRequest);
    Log.i(TAG, "HTTPResponse received in [" + (System.currentTimeMillis()-t) + "ms]");

    HttpEntity entity = response.getEntity();

    if (entity != null) {

        InputStream instream = entity.getContent();
        Header contentEncoding = response.getFirstHeader("Content-Encoding");
        if (contentEncoding != null && contentEncoding.getValue().equalsIgnoreCase("gzip")) {
            instream = new GZIPInputStream(instream);
        }

        // convert content stream to a String
        String resultString= convertStreamToString(instream);
        Log.v(null, "resultString "+resultString);
        instream.close();


        // Transform the String into a JSONObject
        if(resultString!=null){
            jsonObjRecv = new JSONObject(resultString);

        }

        // Raw DEBUG output of our received JSON object:
        Log.i(TAG,"<jsonobject>\n"+jsonObjRecv.toString()+"\n</jsonobject>");

        return jsonObjRecv;

在服务器端，你应该有一个控制器称为一个myController的方法get_employee。在该方法中，你可以处理该请求作为一个正常的HTTP请求和发送响应，JSON，例如

In the server side you should have a get_employee method in a controller called mycontroller. in the method you can process the request as a normal http request and send the response as json eg

employee = Employee.find_by_id(params[:id])
  @js_response = ActiveSupport::JSON.encode(employee)
respond_to do |format|
  format.json { render :json => @js_response} 
  format.html
end

有关CRUD你需要创建不同的方法与像delete_employee合适的参数，update_employee等参考json.org开创的Andr​​oid /解析JSON

for CRUD you need to create different methods with appropriate parameters like delete_employee, update_employee etc. refer json.org to create/parse json in android

这篇关于在Ruby on Rails的针对Android操作系统的API的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！