使用jquery.get的jquery问题 [英] jquery problem using jquery.get
本文介绍了使用jquery.get的jquery问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用jquey.get从其他页面获取结果。
问题是我也在该页面中获得样式和脚本标记。
i简单想要文本值:
for eaxmple我得到的查询输出是
< script src =abc.js/>
hiii
但我只希望hiii作为输出而不是脚本和风格在该页面中调用的标签
i am using jquey.get to get result form other page .
problem is that i also get style and script tag include in that page.
i simple want text value:
for eaxmple what i get output of query is
<script src="abc.js"/>
hiii
but i want only hiii as output not script and style tags called in that page
code for index.php
<script src="jquery-1.10.2.js"></script>
<script>
$( document ).ready(function() {
$.get( "http://localhost/video/b.php", function( data ) {
alert(data );
});
});
</script>k
<div class="result"></div>
and b.php
<link type="text/css" rel="stylesheet" href="http://s.codeproject.com/App_Themes/CodeProject/Css/Main.min.css?dt=2.7.131211.1">
hiii
i get
<link type="text/css" rel="stylesheet" href="http://s.codeproject.com/App_Themes/CodeProject/Css/Main.min.css?dt=2.7.131211.1">
hiii
推荐答案
(文件).ready(function(){
( document ).ready(function() {
.get(http://localhost/video/b.php,function(data){
alert(data) ;
});
});
< / script > k
< div class = result < span class =code-keyword>> < / div >
和b.php
< < span class =code-leadattribute> link type = text / css rel = stylesheet 跨度> <跨度class =code-attribute> href = http://s.codeproject.com/App_Themes /CodeProject/Css/Main.min.css?dt=2.7.131211.1\">
hiii
i获取
< link 类型 = text / css rel = stylesheet href = http://s.codeproject.com/App_Themes/CodeProject/Css/Main.min.css?dt=2.7.131211.1 >
hiii
.get( "http://localhost/video/b.php", function( data ) { alert(data ); }); }); </script>k <div class="result"></div> and b.php <link type="text/css" rel="stylesheet" href="http://s.codeproject.com/App_Themes/CodeProject/Css/Main.min.css?dt=2.7.131211.1"> hiii i get <link type="text/css" rel="stylesheet" href="http://s.codeproject.com/App_Themes/CodeProject/Css/Main.min.css?dt=2.7.131211.1"> hiii
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