ListView中每个节点类型的XML节点 [英] Every XML Node In A Node Type For ListView

问题描述

所以，我想要的是Code自动遍历每个Book寻找Author的子节点并将它们递增到BookListView。这将是一个foreach循环，我认为很可能，你们可以帮助我，因为我几乎就在这里。



i想想像

So, What i would like is the Code to automatically go through every "Book" looking for the child nodes of "Author" and incrementing them to the BookListView. This will be a foreach loop most likely i think, can you guys help me as im nearly here with this please.

i think something like

foreach (authorvariable)
{
BookListView.Items.Add(LVI);
}

XmlDocument xdoc = new XmlDocument();
xdoc.Load(XMLPath);

XmlNode AuthorNode = xdoc.SelectSingleNode("Books/Book/Author");
string AuthorVariable = AuthorNode.InnerText;

ListViewItem LVI = new ListViewItem(AuthorVariable);

BookListView.Items.Add(LVI);

推荐答案

您需要首先获取book节点的集合，然后才能使用foreach循环。

You need to get a collection of "book" nodes first, then you can use your "foreach" loop.

XmlDocument doc = new XmlDocument();
doc.Load("inventory.xml");
//get all books
XmlNodeList books = doc.SelectNodes("//book");
foreach (XmlNode book in books)
{
    // get all authors for each book
    XmlNodeList authors = book.SelectNodes("//author");
    foreach (XmlNode author in authors)
    {
        BookListView.Items.Add(new ListViewItem(author.InnerText));
    }
}

注意：我将此代码基于此 MS XML示例文件 [ ^ ]。我认为我使用的xpath代码足够通用，也适用于你的xml文件，但你可能需要修改SelectNodes语句。



快速好参考是： XPath示例 [ ^ ]

Note: I based this code on this MS XML example file[^]. I think that the xpath code I used is generic enough to also work on your xml file, but you may need to modify the "SelectNodes" statements.

A good quick reference is: XPath Examples[^]

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