xslt地图 [英] xslt map

问题描述

我正在尝试下面的映射，

I am trying to do below mapping,

来源dataformat

source dataformat

< ns0：Root xmlns：ns0 =" http://schemas.microsoft.com/BizTalk/2003/aggschema">

  ; < InputMessagePart_0>

  &NBSP; < ns1：Root xmlns：ns1 =" http：//TestMap.bb_in">

  &NBSP; &NBSP; < value> value_0< / value>

< value> value1< / value>

< value> value2< / value>

< value> value3< / value>

< value> value4< / value>

  &NBSP; < / ns1：Root>

  < / InputMessagePart_0>

  < InputMessagePart_1>

  &NBSP; < ns2：sp_in xmlns：ns2 =" http://TestMap.sp_in">

  &NBSP; &NBSP; < id> 111< / id>

  &NBSP; &NBSP; < name> vvv< / name>

  &NBSP; &NBSP; < class> tenth< / class>

  &NBSP; &NBSP; < school> schoolzphs< / school>

  &NBSP; < / ns2：sp_in>

  < / InputMessagePart_1>

< / ns0：Root>

<ns0:Root xmlns:ns0="http://schemas.microsoft.com/BizTalk/2003/aggschema">
  <InputMessagePart_0>
    <ns1:Root xmlns:ns1="http://TestMap.bb_in">
      <value>value_0</value>
<value>value1</value>
<value>value2</value>
<value>value3</value>
<value>value4</value>
    </ns1:Root>
  </InputMessagePart_0>
  <InputMessagePart_1>
    <ns2:sp_in xmlns:ns2="http://TestMap.sp_in">
      <id>111</id>
      <name>vvv</name>
      <class>tenth</class>
      <school>schoolzphs</school>
    </ns2:sp_in>
  </InputMessagePart_1>
</ns0:Root>

映射：见下面的截图

目的地结果：

< ns0：Root

xmlns：ns0 =" http：//TestMap.output">

< In> 111< / In>

<> vvv< / In>

< In> tenth< / In>

<> schoolzphs< / In>

< In> value_0< / In>

< In> 111< / In>

<> vvv< / In>

<>< tenth< / In>

<> schoolzphs< / In>

< ;在& gt; value1< / In>

<> 111< / In>

<> vvv< / In>

<> ;第十< / In>

<> schoolzphs< / In>

< In> value2< / In>

< In> 111< / In>

< In> vvv< / In>

< In> tenth< / In>

<> schoolzphs< ; / In>

< In> value3< / In>

< In> 111< / In>

<> vvv< /在>

< In> tenth< / In>

<> schoolzphs< / In>

<> ; value4< / In>

< / ns0：Root>

<ns0:Root
xmlns:ns0="http://TestMap.output">
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value_0</In>
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value1</In>
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value2</In>
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value3</In>
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value4</In>
</ns0:Root>

预期结果应为：

< ns0：Root

xmlns ：ns0 =" http：//TestMap.output">

<> 111< / In>

< In> vvv< / In>

< In>十分< / In>

<> schoolzphs< / In>

< In> value_0< / In>

< In> value_1< / In>

< In> value_2< / In>


< In> value_3< / In>

< /跨度>& lt;> value_4< / In>
$
< / ns0：Root>

<ns0:Root
xmlns:ns0="http://TestMap.output">
<In>111</In>
<In>vvv</In>
<In>tenth</In>
<In>schoolzphs</In>
<In>value_0</In>
<In>value_1</In>
<In>value_2</In>
<In>value_3</In>
<In>value_4</In>
</ns0:Root>

此处" value" ;来自源和"In"的元素。来自目的地的元素是无界的。（xml数组类型的字段）

here "value" element from source and "In" element from destination is unbounded.(xml array kind of field)

请一些人帮我使用xslt或任何解决方案。

please some body help me with xslt or any solution.

问候，vishal

推荐答案

试试这个xslt：

Try this xslt:

<?xml version="1.0" encoding="utf-16"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:source="http://schemas.microsoft.com/BizTalk/2003/aggschema" xmlns:ns0="http://TestMap.output" xmlns:ns1="http://TestMap.bb_in" xmlns:ns2="http://TestMap.sp_in" version="1.0" exclude-result-prefixes="source">
  <xsl:template match="source:Root">
    <ns0:Root>
      <xsl:variable name="part0" select="InputMessagePart_0/ns1:Root" />
      <xsl:variable name="part1" select="InputMessagePart_1/ns2:sp_in" />
      <In>
        <xsl:value-of select="

part1 / id" />
< / In>
< In>
< xsl：value-of select ="

part1/id" /> </In> <In> <xsl:value-of select="

part1 / name" />
< / In>
< In>
< xsl：value-of select ="

part1/name" /> </In> <In> <xsl:value-of select="

这篇关于xslt地图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！