正确的方法，使在Android的一个HTTP请求 [英] Proper way to make a HTTP request in Android

问题描述

这是使一个HTTP连接的最佳方式。我的意思是使用代理等。现在，我使用这个：

Which is the best way to make a HTTP connection. I mean using proxies and so on. Now I'm using this one:

StringBuilder entity = new StringBuilder();
entity.append("request body");

AndroidHttpClient httpClient = AndroidHttpClient.newInstance(null);

String proxyHost = android.net.Proxy.getDefaultHost();
int proxyPort = android.net.Proxy.getDefaultPort();
if (proxyHost != null && proxyPort > 0) {
    HttpHost proxy = new HttpHost(proxyHost, proxyPort);
    ConnRouteParams.setDefaultProxy(httpClient.getParams(), proxy);
}
HttpPost httpPost = new HttpPost("https://w.qiwi.ru/term2/xmlutf.jsp");
httpPost.setEntity(new StringEntity(entity.toString(), "UTF-8"));
httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded");
HttpParams params = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(params, 15000);
HttpConnectionParams.setSoTimeout(params, 30000);
httpPost.setParams(params);
HttpResponse httpResponse = httpClient.execute(httpPost);

int responseCode = httpResponse.getStatusLine().getStatusCode();
if (responseCode == HttpStatus.SC_OK) {
    // parsing response
}

我真的不知道这是正常的，因为我的一个客户告诉我，他有一个IllegalArgumentException在他的APN设置设置代理服务器之后。

I'm not really sure if that's ok, because one of my clients tells me he has an IllegalArgumentException right after setting proxy in his APN settings.

推荐答案

使用一种方法称为executeRequest这使得在主机API_REST_HOST实际调用，这种方式（API_REST_HOST能像api.flickr.com一个值Flickr的REST API的HTTP和端口被添加）

Use one method called executeRequest which makes the actual call to the host API_REST_HOST, this way (API_REST_HOST can be a value like "api.flickr.com" for flickr's rest api. The HTTP and the port get added)

 private void executeRequest(HttpGet get, ResponseHandler handler) throws IOException {
    HttpEntity entity = null;
    HttpHost host = new HttpHost(API_REST_HOST, 80, "http");
    try {
        final HttpResponse response = mClient.execute(host, get);
        if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
            entity = response.getEntity();
            final InputStream in = entity.getContent();
            handler.handleResponse(in);
        }
    } catch (ConnectTimeoutException e) {
        throw new ConnectTimeoutException();
    } catch (ClientProtocolException e) {
        throw new ClientProtocolException();
    } catch (IOException e) {
        e.printStackTrace();
        throw new IOException();
    } 
    finally {
        if (entity != null) {
            try {
                entity.consumeContent();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
}

调用此API从这里是这样的：

Call this API from here this way:

final HttpGet get = new HttpGet(uri.build().toString());
    executeRequest(get, new ResponseHandler() {
        public void handleResponse(InputStream in) throws IOException {
            parseResponse(in, new ResponseParser() {
                public void parseResponse(XmlPullParser parser)
                        throws XmlPullParserException, IOException {
                    parseToken(parser, token, userId);
                }
            });
        }
    });

如果你的URI是这样的构造：

Where your uri is constructed like this:

final Uri.Builder builder = new Uri.Builder();
builder.path(ANY_PATH_AHEAD_OF_THE_BASE_URL_IF_REQD);
builder.appendQueryParameter(PARAM_KEY, PARAM_VALUE);

您mClient被声明为一个类级别的变量这样

Your mClient is declared as a class level variable this way

private HttpClient mClient;

和最后的parseResponse可以这样做（说你要解析的XML数据）

and finally your parseResponse can be done in this way(say you want to parse XML data)

private void parseResponse(InputStream in, ResponseParser responseParser) throws IOException {
    final XmlPullParser parser = Xml.newPullParser();
    try {
        parser.setInput(new InputStreamReader(in));

        int type;
        while ((type = parser.next()) != XmlPullParser.START_TAG &&
                type != XmlPullParser.END_DOCUMENT) {
            // Empty
        }

        if (type != XmlPullParser.START_TAG) {
            throw new InflateException(parser.getPositionDescription()
                    + ": No start tag found!");
        }

        String name = parser.getName();
        if (RESPONSE_TAG_RSP.equals(name)) {
            final String value = parser.getAttributeValue(null, RESPONSE_ATTR_STAT);
            if (!RESPONSE_STATUS_OK.equals(value)) {
                throw new IOException("Wrong status: " + value);
            }
        }

        responseParser.parseResponse(parser);

    } catch (XmlPullParserException e) {
        final IOException ioe = new IOException("Could not parse the response");
        ioe.initCause(e);
        throw ioe;
    }
}

这code负责所有可能的异常，并展示了如何正确地解析响应即将从输入流出来的HTTP连接。

This code takes care of all of the possible exceptions and shows how to properly parse response coming from an input stream out of a HTTP connection.

正如你已经知道的请确保您使用一个单独的线程，而不是在UI线程。 就是这样：）

As you already know please make sure you use this in a separate thread and not in the UI thread. That's it :)

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