如何通过RC4算法加密/解密excel文件？ [英] How to encrpy/decrypt excel file via RC4 algorithm?

问题描述

我正在执行以下代码并能够传递字符串值并获得所需的结果。但是我想通过数据传递excel文件的路径并使用数据加密excel文件的传递路径，然后通过RC4解密加密的excel文件的传递路径。



我试过的代码如下传递字符串值并获得所需的结果（加密/解密）。

public static string RC4（string input，string key）{

StringBuilder result = new StringBuilder（）;

int x，y，j = 0;

int [] box = new int [256]; for（int i = 0; i< 256; i ++）

{box [i] = i;对于（int i = 0; i< 256; i ++）{j =（key [i％key.Length] + box [i] + j）％256; $ b / b x = box [i]; box [i] = box [j]; box [j] = x; for（int i = 0; i< input.Length; i ++）{y = i％256; j =（box [y] + j）％256; x = box [y]; box [y] = box [j]; box [j] = x; result.Append（（char）（input [i] ^ box [（box [y] + box [j]）％256]））;返回result.ToString（）;}

I am doing following code and able to pass string values and get desired results. But I want to pass the path of the excel file with data and encrypt the passed path of the excel file with data and then decrypt the passed path of the encrypted excel file with data via RC4.

Code I tried is as follows to pass string values and get desired results(encrypt/decrypt).
public static string RC4(string input, string key){
StringBuilder result = new StringBuilder();
int x, y, j = 0;
int[] box = new int[256]; for (int i = 0; i < 256; i++)
{ box[i] = i; }
for (int i = 0; i < 256; i++) { j = (key[i % key.Length] + box[i] + j) % 256; x = box[i]; box[i] = box[j]; box[j] = x; } for (int i = 0; i < input.Length; i++) { y = i % 256; j = (box[y] + j) % 256; x = box[y]; box[y] = box[j]; box[j] = x; result.Append((char)(input[i] ^ box[(box[y] + box[j]) % 256])); } return result.ToString();}

推荐答案

这不是它的工作原理;你不能像过去那样来发布你的要求，并期望有人为你提供符合你需求的完整工作解决方案。



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