如何打破URL的字符串? [英] how to break the string of URLs?
问题描述
我有一串URL,我需要使用http作为索引来破坏URL .Below是我的字符串示例。
string X = http://www.yachtbroker.dk/ _publicPics / Boats443B.JPGhttp://www.yachtbroker.dk/_publicPics/Boats/543B.gifhttp://yachtbrokerdk/_publicPics/Boats/idue.jpeg
how实现它?
I have a string of URLs and i need to break the urls using "http" as index.Below is my string example.
string X= http://www.yachtbroker.dk/_publicPics/Boats443B.JPGhttp://www.yachtbroker.dk/_publicPics/Boats/543B.gifhttp://yachtbrokerdk/_publicPics/Boats/idue.jpeg
how to achieve it?
推荐答案
有两种方法:
There are a couple of ways:
string[] urls = inputString.Split(new string[] {"http://"}, StringSplitOptions.RemoveEmptyEntries);
是最简单的,但如果以后需要,你需要将http://部分添加回每个字符串。
替代方法是使用正则表达式,这有点复杂,但可以保留完整的URL。
Is the simplest, but you will need to add the "http://" part back onto each string if you need it later.
The alternative is to use a Regex, which is a little more complex, but could preserve the complete URL.
Hi Ahmed
用户RE GEX解决它..
尝试这样..
Hi Ahmed
user REGEX to resolve it..
try like this..
string url = "http://www.yachtbroker.dk/_pblicPics/Boats443B.JPGhttp://www.yachtbroker.dk/_publicPics/Boats/543B.gifhttp://yachtbrokerdk/_publicPics/Boats/idue.jpeg";
string[] urls = Regex.Split(url, @"http://");
删除数组中的空字符串。
使用此...
to remove the empty string in the array.
use this..
string[] urls = Regex.Split(url, @"http://").Where(k => !string.IsNullOrWhiteSpace(k)).ToArray();
尝试此代码...
< br $>
try this code...
string url = "http://www.yachtbroker.dk/_publicPics/Boats443B.JPGhttp://www.yachtbroker.dk/_publicPics/Boats/543B.gifhttp://yachtbrokerdk/_publicPics/Boats/idue.jpeg";
string token = "http://";
var urls = url.Split(new string[] { token }, StringSplitOptions.RemoveEmptyEntries).Select(k => token + k).ToArray();
尝试下面的代码
try below code
string X = "http://www.yachtbroker.dk/_publicPics/Boats443B.JPGhttp://www.yachtbroker.dk/_publicPics/Boats/543B.gifhttp://yachtbrokerdk/_publicPics/Boats/idue.jpeg";
string[] values = X.Split(new string[] { "http" }, StringSplitOptions.None);
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