如何获得圆值 [英] How to get round value

问题描述

我正在装箱申请

我想要给定/计算金额的一周。



如果计算的金额是1.2那么它给了1

I am crating one application
I want to round of the given/Calculated amount.

if the calculated amount is 1.2 then it gives 1

Math.Round(95.55)

输出为96



但当我使用

Math.Round时，当计算出的金额大于1.5时显示2



但我想要



输入为1.2然后输出为2



请帮帮我...

提前致谢..

output is 96

but when i use the
Math.Round then it show 2 when the calculated amount is greater than 1.5

but i want

input is 1.2 then output is 2

Please help me...
Thanks in advance..

推荐答案

的正确（已验证）输出当输入 1.2时，Math.Round 是

• 1.0 输入 95.55

The correct (verified) output of Math.Round is

• 1.0 when input is 1.2
• 96 when input is 95.55

引用：

当输入的值为1.01时，我想要舍入值然后是s如何2

i想要这样..

是否可能

I want round value when the entered value is 1.01 then it show 2
i want like this ..
is it possible

是的，有可能：使用 Math.Ceiling [ ^ ]而不是 Math.Round 。



[/ update]



[update 2]

Yes, it is possible: use Math.Ceiling[^] instead of Math.Round.

[/update]

[update 2]

引用：

我尝试了Math.Ceiling，但它给出了与Math相同的内容.Round

i am tried "Math.Ceiling" but it gives out same as a "Math.Round"

他们不会给出相同的结果，请尝试：

They do NOT give 'the same results', try:

Dim a() As Double = {1.2, 95.55}
Dim ro(2) As Double
Dim ce(2) As Double


ro(0) = Math.Round(a(0))
ro(1) = Math.Round(a(1))
ce(0) = Math.Ceiling(a(0))
ce(1) = Math.Ceiling(a(1))

Console.WriteLine("ro(0)={0}, ro(1)={1}", ro(0), ro(1))
Console.WriteLine("ce(0)={0}, ce(1)={1}", ce(0), ce(1))

[/ update 2]

Dim ldblamount as double



ldblamount = val（100.01）



如果Int（ldblamount）<> ldblamount然后

ldblamount = Int（ldblamount）+ 1

结束如果





'结果

我的价值结果

100.00 100

100.01 101

100.99 101

Dim ldblamount as double

ldblamount = val("100.01")

If Int(ldblamount) <> ldblamount Then
ldblamount = Int(ldblamount) + 1
End If


'Result
I Value Result
100.00 100
100.01 101
100.99 101

您好，我是该站点的新成员试试这个-Int（-1.2）对我来说没问题

Hi, am a new member on the site try this -Int(-1.2) works ok for me

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