发布下拉框的选定项目 [英] post dropdown box's selected item

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本文介绍了发布下拉框的选定项目的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

<form class="clearfix" action="reg_account.php" method="post">
                            <div class="clearfix" style="padding-removed 34%;">
                                <input type="text" class="small-text" placeholder="User Name" name="name">
                            </div>
                            <div class="clearfix" style="padding-removed 34%; padding-removed 2px;">
                                <input type="text" class="small-text" placeholder="Registration ID" name="id">
                            </div>
                            <div class="clearfix" style="padding-removed 34%; padding-removed 2px;">
                                <input type="text" class="small-text" placeholder="Password" name="password">
                            </div>

                            <div class="clearfix" style="padding-removed 34%; padding-removed 2px;">
                                <input type="text" class="small-text" placeholder="Reference" name="reference">

                            </div>

                            <div class="clearfix" style="padding-removed 34%; padding-removed 2px;">
                                <input type="text" class="small-text" placeholder="Placement ID" name="placementid">
                            </div>
                            <br>
                            <div class="clearfix" style="padding-removed 34%;">
                                <select id="eproducts" name="cscf[producttype]" style="color: blue; width: 310px; text-align: center; background-color:captiontext">
                                    <!--                                    <option>------ Select Products ------</option>-->
                                    <?php echo "<option>---------------- Select Products ----------------</option>"; ?>
                                    <?php
                                    $query = "SELECT sl, types from `products`";
                                    $result = mysql_query($query) or die($query . "<br/><br/>" . mysql_error());
                                    while ($row = mysql_fetch_array($result)) {
                                        echo "<option value='" . $row['id'] . "'>" . $row['types'] . "</option>";
                                    }
                                    ?>
                                </select>
                                <input type="text" name="producttype" id="product_hidden">


                            </div>

                            <input type="submit" class="btn green" value="Registration">
                        </form>







<script>
            $(document).ready(function() {
                $("#eproducts").change(function(){
                    $("#product_hidden").val(("#eproducts").find(":selected").text());

                });
            });
        </script>





但是,当我按下提交按钮时,它不发布产品类型或当我更改所选项目时,它在文本框中不显示值。请帮帮我

推荐答案

查询 = SELECT sl,来自`products`的类型;
query = "SELECT sl, types from `products`";


result = mysql_query(
result = mysql_query(


query) die(
query) or die(


这篇关于发布下拉框的选定项目的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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