动态创建的链接按钮命令事件不是触发 [英] dynamically created Link Button command event is not Firing

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本文介绍了动态创建的链接按钮命令事件不是触发的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

  private   void  CreateLinkBut​​ton( string  commandArgument, string  tidshow)
{
string [] show = tidshow.Split(' *');

innerTableCell = new HtmlTableCell();
System.Web.UI.HtmlControls.HtmlGenericControl createDiv =
new System.Web.UI.HtmlControls.HtmlGenericControl( DIV);

// createDiv.Style.Add(HtmlTextWriterStyle.BackgroundColor,cyan);
// createDiv.Style.Add(HtmlTextWriterStyle.Color,Red);
createDiv.Style.Add(HtmlTextWriterStyle.Height, 25px);
createDiv.Style.Add(HtmlTextWriterStyle.Width, 150px);
createDiv.Style.Add(HtmlTextWriterStyle.Position, relative);
createDiv.Style.Add(HtmlTextWriterStyle.VerticalAlign, false);
UpdatePanel up = new UpdatePanel();
up.ID = up + tidshow;


LinkBut​​ton linkBut​​ton = new LinkBut​​ton
{
ID = tidshow,
Text = show [ 1 ],
CommandArgument = commandArgument,
};

// linkBut​​ton.OnClientClick =ShowPopup();;
linkBut​​ton.Command + = this .linktest_Click;
linkBut​​ton.CausesValidation = false ;
linkBut​​ton.EnableViewState = true ;
linkBut​​ton.ToolTip = 快速填充;
linkBut​​ton.Style.Add(HtmlTextWriterStyle.BorderColor, green);
up.ContentTemplateContainer.Controls.Add(linkBut​​ton);
createDiv.Controls.Add(up);
innerTableCell.Controls.Add(createDiv);
innerTableRow.Cells.Add(innerTableCell);

}

受保护 void linktest_Click(< span class =code-sdkkeyword> Object sender,CommandEventArgs e)
{
flag = 允许 ;
ViewState [ isPostBackOfOutputPage] = ;

ViewState [ path] = @ e.CommandArgument.ToString( );

show(e.CommandArgument.ToString());
}

解决方案

这是向按钮添加事件处理程序的方法:

 linkBut​​ton.Click + = new EventHandler(this.linktest_Click); 


使用oninit()问题解决了。



感谢

 swapnil_jadhav 

< pre lang = cs > 受保护的覆盖void OnInit(EventArgs e)
{
base.OnInit(e);
CreateLinkBut​​ton();

} < / pre >


private void CreateLinkButton(string commandArgument, string tidshow)
        {
            string[] show = tidshow.Split('*');

            innerTableCell = new HtmlTableCell();
            System.Web.UI.HtmlControls.HtmlGenericControl createDiv =
             new System.Web.UI.HtmlControls.HtmlGenericControl("DIV");

          //  createDiv.Style.Add(HtmlTextWriterStyle.BackgroundColor, "cyan");
            // createDiv.Style.Add(HtmlTextWriterStyle.Color, "Red");
            createDiv.Style.Add(HtmlTextWriterStyle.Height, "25px");
            createDiv.Style.Add(HtmlTextWriterStyle.Width, "150px");
            createDiv.Style.Add(HtmlTextWriterStyle.Position, "relative");
            createDiv.Style.Add(HtmlTextWriterStyle.VerticalAlign, "false");
            UpdatePanel up = new UpdatePanel();
            up.ID = "up" + tidshow;
            

          LinkButton linkButton = new LinkButton
            {
                ID = tidshow,
                Text = show[1],
                CommandArgument = commandArgument,
            };

           // linkButton.OnClientClick = "ShowPopup();";
            linkButton.Command += this.linktest_Click;
            linkButton.CausesValidation = false;
            linkButton.EnableViewState = true;
            linkButton.ToolTip = "Filling Fast";
            linkButton.Style.Add(HtmlTextWriterStyle.BorderColor, "green");
            up.ContentTemplateContainer.Controls.Add(linkButton);
            createDiv.Controls.Add(up);
            innerTableCell.Controls.Add(createDiv);
            innerTableRow.Cells.Add(innerTableCell);

        }

        protected void linktest_Click(Object sender, CommandEventArgs e)
        {
            flag = "allow";
            ViewState["isPostBackOfOutputPage"] = "yes";

            ViewState["path"] = @e.CommandArgument.ToString();

            show(e.CommandArgument.ToString());
        }

解决方案

This is how you add an eventhandler to the button:

linkButton.Click += new EventHandler(this.linktest_Click);


using oninit() problem is solved.

thanks to

swapnil_jadhav

<pre lang="cs">protected override void OnInit(EventArgs e)
    {
        base.OnInit(e);
        CreateLinkButton();

    }</pre>


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