Linux中的Linux运行过程 [英] Linux run process in BG
问题描述
Hello All,
以下是我的代码;
echo输入时间
读取fname1
睡眠fname1&
echo有美好的一天
我需要在这个过程中睡觉这段时间,这个时间取自后台的用户(fname1)。当我尝试使用上面的代码时,它没有正确执行。它会跳过睡眠和背景。
你能不能帮我解决这个问题。
谢谢。
Hello All,
Following is my code;
echo "Enter time"
read fname1
sleep fname1 &
echo "have a nice day"
I need to sleep this process for such amount of time which taken from user (fname1) in background. when I try using above code it didn't execute properly. It skips the sleep and background.
Could you please help me to solve this.
Thank you.
推荐答案
这个任务对我来说听起来没有意义。
在后台运行一个进程意味着:
stell将该命令作为后台进程启动(触发并忘记)并立即继续执行下一个命令。
即这立刻就完成了:
The task sounds non-sense to me.
Running a process in background means:
the stell starts that command as background process (fire and forget) and immediately continues with the next command.
I.e. this completes instantly:
sleep 100 &
echo "done"
您可以观察 sleep
流程通过运行 ps
命令。
干杯
Andi
PS:在你的情况下,在背景中是无意义的。离开&
。
PPS:如果你想让睡眠和回声进入一个后台进程,请执行以下操作:
读取-p输入秒数:秒; (睡眠
You may observe the sleep
process by running the ps
command.
Cheers
Andi
PS: In your case, the "in background" is non-sense. Leave away the &
.
PPS: If you want the sleep and the echo go into one background process, do this:
read -p "Enter seconds: " sec; (sleep
sec; echo度过愉快的一天)& 。
sec; echo "have a nice day") &.
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