没有足够的上下文信息来确定类型错误如何解决 [英] insufficient contextual information to determine type error how to solve

问题描述

错误是没有足够的上下文信息来确定类型。

有错误的代码是：

The errors is insufficient contextual information to determine type.
The codes that have the errors are:

getData.setx(x);
getData.sety(y);
getData.setsunType(sunType);

和所有getdata.set

and all the getdata.set

MissionPlan::MissionPlan()
{
    int choice;
    switch(choice)
    {
        cout<<"Input statistical data"<<endl;
        cout<<"Please enter x-cordinate:";
        cin>> x;
        getData.setx(x);
        
        cout<<"Please enter y-cordinate:";
        cin>>y;
        getData.sety(y);
        
        cout<<"Please enter sun type: TYPE:";
        cin>>sunType;
        getData.setsunType(sunType);
        
        cout<<"Please enter no. of earth-like planets:";
        cin>>noOfEarthLikePlanets;
        getData.setnoOfEarthLikePlanets(noOfEarthLikePlanets);
        
        cout<<"Please enter no. of earth-like moons:";
        cin>>noOfEarthLikeMoons;
        getData.setnoOfEarthLikeMoons(noOfEarthLikeMoons);
        
        cout<<"Please enter ave. particulate density (%-tage):";
        cin>>aveParticulateDensity;
        getData.setaveParticulateDensity(aveParticulateDensity);
        
        cout<<"Please enter ave. plasma density (%-tage):";
        cin>>avePlasmaDensity;
        getData.setavePlasmaDensity(avePlasmaDensity);

推荐答案

这不是有效的开关声明，例如参见切换C ++参考 [ ^ ]。

That's not a valid switch statement, see, for instance "switch" at C++ reference[^].

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