我如何从C#中的表单数据传输中获取表单 [英] How I a form from a form data transfer in C#

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问题描述

嗨。我如何从C#中的表格数据传输中获取表格

Hi.How I a form from a form data transfer in C#

推荐答案

问题不是很清楚,但最有可能的是,它可以简化为关于表单协作的流行问题。



最强大的解决方案是在表单类中实现适当的接口并传递接口引用而不是引用整个实例表单。有关更多详细信息,请参阅我以前的解决方案:如何以两种形式复制列表框之间的所有项目 [ ^ ]。



另请参阅此处的其他解决方案讨论。如果应用程序足够简单,解决方案就像在一个表单中声明一些 internal 属性并将对一个表单的实例的引用传递给另一个表单的实例一样简单形成。对于更复杂的项目,这种违反严格封装的样式和松散耦合可能会增加代码的意外复杂性并引发错误,因此封装良好的解决方案将是优惠。



另请参阅:

http://en.wikipedia.org/wiki/Accidental_complexity [ ^ ],

http://en.wikipedia.org/wiki/Loose_coupling [ ^ ]。



-SA
The question is not quite clear, but most likely, it can be reduced to the popular question about form collaboration.

The most robust solution is implementation of an appropriate interface in form class and passing the interface reference instead of reference to a "whole instance" of a Form. Please see my past solution for more detail: How to copy all the items between listboxes in two forms[^].

Please also see other solutions in this discussion. If the application is simple enough, the solution could be as simple as declaring of some internal property in one form and passing a reference to the instance of one form to the instance of another form. For more complex projects, such violation of strictly encapsulated style and loose coupling could add up the the accidental complexity of the code and invite mistakes, so the well-encapsulated solution would be preferable.

Please see also:
http://en.wikipedia.org/wiki/Accidental_complexity[^],
http://en.wikipedia.org/wiki/Loose_coupling[^].

—SA


如果您的意思是在应用程序中将数据从一个表单传输到另一个表单,那么它取决于表单之间的关系。试试这些:

在两个表格之间传递信息,第1部分:父母与孩子 [ ^ ]

在两种表格之间传递信息,第2部分:儿童到父母 [ ^ ]

在两种形式之间传递信息,第3部分:儿童到儿童 [ ^ ]
If you mean transfer data from one form to another within your application, then it depends on the relationship between the forms. Try these:
Transferring information between two forms, Part 1: Parent to Child[^]
Transferring information between two forms, Part 2: Child to Parent[^]
Transferring information between two forms, Part 3: Child to Child[^]


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