从GOOGLE API返回的JSON中获取数据 [英] Get data from JSON which is returned from GOOGLE API

问题描述

嗨朋友们，



我正在开发一个应用程序，其要求就像根据用户的国家/地区选择国家/地区下拉列表一样。



例如：如果我的申请用户来自新加坡，那么应该在下拉菜单中选择新加坡，如果来自印度，则应选择印度。



要做到这一点，我使用的是Google API， Google API [ ^ ]，它返回一个JSON对象。现在我想从这个JSON对象中仅获取国家名称。



我保持断点并且能够在浏览器中看到返回的JSON对象。但是如何从这里获得国家名称？



任何建议朋友......？

Hi Friends,

I'm developing a application in that the requirements are like making the country drop down list selected based on the user's country.

For ex: If the user of my application is from Singapore then singapore should be selected in the drop down and if from India , then India should be selected.

To do this I'm using Google API, Google API[^], and it is returning a JSON object. Now I want to fetch only country name from this JSON object.

I kept break point and able to see the returned JSON object in browser. But how to get the Country name from this?

Any suggestions friends...?

推荐答案

您好Tejas，



您现在的位置：



添加对Newtonsoft.Json的引用;

Hi Tejas,

Here you go:

Add reference to Newtonsoft.Json;

using Newtonsoft.Json;

这里获取国家代码：

Here the code to get Country:

WebClient wc = new WebClient(); // here I'm using Web Client to get the JSON data frm GMaps API for demo., you're free to use of your choice.

var jsonStr = wc.DownloadString("http://maps.googleapis.com/maps/api/geocode/json?latlng=17.37528,78.47444&sensor=false");
           JObject a = JObject.Parse(jsonStr);
           var addresses = a["results"][0]["formatted_address"].ToString();
           var country = addresses.Split(',')[(addresses.Split(',').Length - 1)].Trim();

希望它有所帮助。



快乐编码：）

Hope it helps.

Happy Coding :)

查看此链接。您将了解如何从中获取数据。



Deserialize Json [ ^ ]



问候..

See this link. You will get an idea regarding how to get data out of it.

Deserialize Json[^]

Regards..

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