我有一个问题是在ACCESS中开发一个我需要帮助的工具。 [英] I have an issue will developing a tool in ACCESS that I need help with.
问题描述
您好，
我希望我在正确的区域发布此信息以获得一些帮助。
我正在努力我在使用Microsoft ACCESS 2010工作时使用的访问工具，并遇到了一个问题。如果有人可以帮助我解决我遇到的问题，我会非常感激，我这是一个完整的NOVICE，在这种情况下，我不知道我在这方面做错了什么。
我遇到的问题是关于我创建的应用程序的退出功能。当我选择"退出"时我在表达式中收到"语法错误（缺少运算符）"的错误消息。其他一切似乎都能正常工作，直到我达到
这一点，有人可以帮助我并告诉我需要做些什么来纠正这个问题。下面是我正在尝试的功能的代码。
Private Sub cmdLogOut_Click
On Error GoTo Err_cmdLogOut_Click
Dim intResponse As Integer
Dim db A DAO.Database
Dim rst DAO.Recordset
设置db = CurrentDb（）
设置rst = db.OpenRecordset（" ztbluserlog"，dbOpenDynaset）
Forms！fmnuMainMenu.visible = False
intResponse = MsgBox（"你确定要退出吗？"，vbYesNo + vbExckenation，"退出系统" ;）
选择案例intResponse
案例vbYes
rst.FindLast" SecurityID ="  &安培; User.Security.ID
rst.Edit
rst！TimeOut = Now（）
rst。更新
DoCmd.Quit
Case Else
表格！fmnuMainMenu.Visible = True
结束选择
Exit_cmdLogOut_Click：
退出子
Err_cmdLogOut_Click：
MsgBox Err.Description
恢复Exit_cmdLogOut_Click
End Sub
任何帮助将不胜感激。
您好Pfales，
此论坛的目的是支持开放规范文档。您可以在此处阅读Microsoft Open Specifications计划，
http://www.microsoft.com /openspecifications/en/us/default.aspx
您似乎没有实施引用的协议之一。如果您是，请纠正我并告诉您有哪些文件（最好是哪个部分）。
也许您的问题属于Access Developer论坛，请检查：
https://social.msdn.microsoft。 com /论坛/ en-US / home？论坛= accessdev& filter = alltypes& sort = lastpostdesc
关心，
Vilmos Foltenyi - MSFT
Hello,
I hope I am posting this in the correct area to receive some assistance.
I am working on an Access tool for my use at work using Microsoft ACCESS 2010 and have come across an issue. If anyone can assist me with the problem I am having I would greatly appreciate it, I am a complete NOVICE at doing this and I don't know what I am doing wrong in this case.
The issue I am having is regarding the exit function from the application I have created. When I select "Exit" I get an error message of, "Syntax error (missing operator) in expression. Everything else seems to work correctly until I get to this point, could someone assist me and tell me what I need to do to correct the issue. Below is the code for the function I am trying to do.
Private Sub cmdLogOut_Click
On Error GoTo Err_cmdLogOut_Click
Dim intResponse As Integer
Dim db A DAO.Database
Dim rst A DAO.Recordset
Set db=CurrentDb()
Set rst=db.OpenRecordset ("ztbluserlog", dbOpenDynaset)
Forms !fmnuMainMenu.visible = False
intResponse = MsgBox ("Are you sure you wish to log out?", vbYesNo + vbExckenation, "Exiting System")
Select Case intResponse
Case vbYes
rst.FindLast "SecurityID = " & User.Security.ID
rst.Edit
rst!TimeOut = Now()
rst.Update
DoCmd.Quit
Case Else
Forms!fmnuMainMenu.Visible = True
End Select
Exit_cmdLogOut_Click:
Exit Sub
Err_cmdLogOut_Click:
MsgBox Err.Description
Resume Exit_cmdLogOut_Click
End Sub
Any assistance will be greatly appreciated.
Hi Pfales,
The purpose of this forum is to support the Open Specifications documentation. You can read about the Microsoft Open Specifications program here, http://www.microsoft.com/openspecifications/en/us/default.aspx
It doesn’t appear that you are implementing one of the protocols cited. If you are, please correct me and tell which document (and preferably which section) you have problem with.
Perhaps your question rather belongs to the Access Developer forum, please check:
https://social.msdn.microsoft.com/Forums/en-US/home?forum=accessdev&filter=alltypes&sort=lastpostdescRegards,
Vilmos Foltenyi - MSFT
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