如何在不使用.Split（）的情况下将字符串拆分为字符串数组 [英] How to split A string into Array of Strings without using .Split()

问题描述

hye

我想将字符串拆分为一个字符串数组但我必须不使用string.Split（）方法c＃提供



任何可以帮助我的人？ thanx

hye
I want to split the string into An array of string but i have to do it without using string.Split() method c# provides

Anyone who could help me? thanx

推荐答案

好吧，作为解决方案，我建议您查看以下链接：



MSDN字符串类定义 [ ^ ]

在那里，看看方法：



IndexOf，SubString，替换。



有了它们你就可以轻松运行一些for循环并复制split功能。



给你的作业一个去看看你是怎么过的。

Well, as a solution I suggest you check out the following link:

MSDN String Class Definition[^]
On there, Look at the methods:

IndexOf, SubString, Replace.

With them you could easily run some for loop and replicate the "split" function.

Give your homework a go and see how you get on.

你可以把你自己的分割方法作为

You can crate your own split method as

public String[] SplitText(String txt, char[] delim)
        {
            if (txt == null)
                return new String[0]; // or exception
            if (delim == null || delim.Length == 0)
                return new String[0]; // or exception

            char[] text = txt.ToCharArray();
            string[] result = new string[1]; // If there is no delimiter in the string, return the whole string
            int part = 0;
            int itemInArray = 1;

            for (int i = 0; i < text.Length; i++)
            {
                if (IsIn(delim, text[i]))
                {
                    Array.Resize(ref result, ++itemInArray); // Is it consider as a framework method ???
                    part++;
                }
                else
                    result[part] += text[i];
            }
            return result;
        }
        public static Boolean IsIn(char[] delim, char c)
        {
            for (int i = 0; i < delim.Length; i++)
                if (c == delim[i])
                    return true;
            return false;
        }

然后像这样叫它

and then call it like this

char[] delimter = new char[1];
delimter[0] = '-';
string[] b = SplitText("Your-string-goes-here", delimter);

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