通过N No of DaysDifference获取当前日期 [英] Getting current date by N No of DaysDifference

问题描述

嘿朋友我遇到问题请帮助我。



我有开始日期和结束日期以及我有NoofDaysDifference可能是1,2， 3,5,7,10,12,15,18,20,25,30。



我必须以（1或2或3或5或7或10之类的明智）NoofDaysDifference月/总持续时间。



当前日期应减少NoofDaysDifference。



我这样做每天都这样做

Hey friends i am facing a problem please help me.

I have Start date and End Date as well as i have NoofDaysDifference which could be 1,2,3,5,7,10,12,15,18,20,25,30.

I have to get current date on the basis No of (1 or 2 or 3 or 5 or 7 or 10 like wise) NoofDaysDifference in month/total duration.

Current Date should be decrement by NoofDaysDifference.

I have done for every one days like this

int NoofDays;

NoofDays = dtEnd.Subtract(dtstart).Days;

while (dtEnd.Date > dtstart.Date && NoofDays >= 0)
{
   DateTime CurrentDate = dtstart.AddDays(NoofDays);
   NoofDays--;
}

推荐答案

您的问题不明确。以下是日期计算的两个示例。这些中的任何一个都接近您的要求吗？如果没有，请使用改善问题并使用真实日期显示一些示例，以说明您要做的事情。





示例1

Your question is not clear. Here are two examples of date computations. Do either of these come close to your requirements? If not, please use Improve Question and show a few examples using real dates that will demonstrate what you are trying to do.


Example 1

StringBuilder strOutput = new StringBuilder(4096);
DateTime dtStart = DateTime.Parse("2013-09-01");
DateTime dtEnd = DateTime.Parse("2013-09-05");
int NoOfDays=3;
DateTime dt;
dt = dtStart.Date;
while (dt <= dtEnd)
{
    strOutput.AppendLine(dt.ToString("yyyy-MM-dd"));
    dt=dt.AddDays(NoOfDays);
}
Console.WriteLine(strOutput);

输出

2013-09 -01

2013-09-04





示例2

Output
2013-09-01
2013-09-04


Example 2

DateTime dtStart = DateTime.Parse("2013-09-01");
DateTime dtEnd = DateTime.Parse("2013-09-05");
int NoOfDays;
DateTime dt;
NoOfDays = dtEnd.Subtract(dtStart).Days;
dt = DateTime.Now.Date.AddDays(-(double)NoOfDays);
Console.WriteLine("Start: " + dtStart.ToString("yyyy-MM-dd") + ", End: " + dtEnd.ToString("yyyy-MM-dd"));
Console.WriteLine("Days Difference: " + NoOfDays );
Console.WriteLine("Now=" + DateTime.Now.Date.ToString("yyyy-MM-dd") + ", Computed Date=" + dt.Date.ToString("yyyy-MM-dd"));

输出

开始时间：2013-09-01，结束日期：2013-09-05

天差：4

现在= 2013-09-06，计算日期= 2013-09-02



注意：时间值包含在DateTime类中存储的值中。您可以在显示DateTime Class值时使用字符串格式以不显示时间部分。

Output
Start: 2013-09-01, End: 2013-09-05
Days Difference: 4
Now=2013-09-06, Computed Date=2013-09-02

Note: A time value is included in the value stored in the DateTime Class. You can use string formatting when displaying a DateTime Class value to not display the time portion.

if（ddlScheduledMedicines.SelectedIndex == 1）

{

daysdifference = 3;

}

else if（ddlScheduledMedicines.SelectedIndex == 2）

{

daysdifference = 5;

}

else if（ddlScheduledMedicines.SelectedIndex == 3）

{

daysdifference = 7;

}



DateTime CurrentDate = dtstart.Date;



而（CurrentDate< dtEnd）

{

CurrentDate = CurrentDate.AddDays（ daysdifference）;

}

if (ddlScheduledMedicines.SelectedIndex == 1)
{
daysdifference = 3;
}
else if (ddlScheduledMedicines.SelectedIndex == 2)
{
daysdifference = 5;
}
else if (ddlScheduledMedicines.SelectedIndex == 3)
{
daysdifference = 7;
}

DateTime CurrentDate =dtstart.Date;

while (CurrentDate<dtEnd)
{
CurrentDate = CurrentDate.AddDays(daysdifference);
}

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