Xml文档需要在每个文件中获取相同的标记名称节点列表 [英] Xml document need to get the same tag name nodes list in each

问题描述

HI，



我在下面显示XML文档



当我试图收集xmlnodes列表< attribute>节点我得到XML文档中存在的所有节点我只需要得到< attributes>节点作为基于< subject type =>的列表。内部文本可以帮助我。



我的代码收集attribut的节点列表：

I have XML document displayed below

When i am try to gather the xmlnodes list of <attribute> nodes i am getting all the nodes existed in the XML doc i need only to get the <attributes> Nodes as a list based on <subject type=""> inner text could any one help me.

My Code to gathers the node list of attribut :

XmlNodeList elemList = xdoc.DocumentElement.GetElementsByTagName("Attribute");

<eLinkResult>
<LinkSet>
<DbFrom>pubmed</DbFrom>
<IdUrlList>
<IdUrlSet>
<Id>20888710</Id>
<ObjUrl>
<Url>
http://linkinghub.elsevier.com/retrieve/pii/S0360-3016(10)00875-8
</Url>
<IconUrl LNG="EN">
//www.ncbi.nlm.nih.gov/corehtml/query/egifs/http:--linkinghub.elsevier.com-ihub-images-PubMedLink.gif
</IconUrl>
<SubjectType>publishers/providers</SubjectType>
<Category>Full Text Sources</Category>
<Attribute>full-text online</Attribute>
<Attribute>publisher of information in url</Attribute>
<Attribute>subscription/membership/fee required</Attribute>
<Provider>
<Name>Elsevier Science</Name>
<NameAbbr>ES</NameAbbr>
<Id>3048</Id>
<Url LNG="EN">http://www.elsevier.com/</Url>
</Provider>
</ObjUrl>
<ObjUrl>
<Url>
https://www.clinicalkey.com/content/playBy/pii?v=S0360-3016(10)00875-8
</Url>
<IconUrl LNG="EN">
//www.ncbi.nlm.nih.gov/corehtml/query/egifs/http:--dgb32t5jlo8kf.cloudfront.net-images-clinicalkey_linkout.png
</IconUrl>
<SubjectType>aggregators</SubjectType>
<Category>Full Text Sources</Category>
<Attribute>full-text online</Attribute>
<Attribute>subscription/membership/fee required</Attribute>
<Provider>
<Name>Clinical Key</Name>
<NameAbbr>clinicalk</NameAbbr>
<Id>8412</Id>
<Url LNG="EN">http://www.clinicalkey.com</Url>
</Provider>
</ObjUrl>

在此XML中，我想基于上面的Sibiling节点SsubjectType收集所有Attribute节点，并在列表中创建此Attribute节点。请帮助我







提前进行..提升..

IN this XML i would like to gather all the Attribute nodes based on the above Sibiling node SsubjectType and make this Attribute nodes in a list. pls help me



Thnaks in Advance..

推荐答案

您好Ravi，

您可以通过以下方式使用Linq获取元素。



示例XML文件

Hi Ravi,
You can fetch the elements by using Linq by following way.

Sample XML File

<family>
	<member>
		Abhishek Shukla
	</member>
	<member>
		Prateek Shukla
	</member>
	<member>
		Saurabh Shukla
	</member>
	<member>
		Sachin Shukla
	</member>
	<member>
		Vibhor Tiwari
	</member>
	<member>
		Tanmaya Dixit
	</member>
</family>

Linq代码

Linq Code

XDocument doc =   XDocument.Load(System.IO.Path.Combine(AppDomain.CurrentDomain.SetupInformation.ApplicationBase, "Family.xml"));

var temp = from node in doc.Descendants("Member")
where node.Value.Trim().Equals("Abhishek Shukla",StringComparison.OrdinalIgnoreCase)
select node;

别忘了添加命名空间System.XMl.Linq



希望这会有所帮助！

Don't forget to Add namespace System.XMl.Linq

Hope this helps!

看一下使用XPath的其他解决方案（ http://www.w3schools.com/xpath/ [ ^ ]）这里给出：如何使用gi获取xml数据ven关键字 [ ^ ]和这里：在XML中查找特定单词 [ ^ ]。

Take a look at some other solutions using XPath (http://www.w3schools.com/xpath/[^]) given here: how can i get the xml data by using given keyword[^] and here: Find Specific Word in XML[^].

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