mdi容器父n子 [英] mdi Container parent n child

问题描述

我的应用程序有3种形式（form1，form2，form3）。 Form1是form2的父容器，当form2调用form3时出现在form1的外面。我的问题如何让form3出现在form1中？



CodeSnippet：

My application has 3 forms(form1,form2,form3). Form1 is parent container of form2 and when form2 calls form3 appears out side the form1. And my question how can i make form3 appear within form1??

CodeSnippet:

//FORM1 code
FORM2 f2=new FORM2();
f2.Mdiparent=this;               ///Call a instance of Form2
f2.Show();

//FORM2 code
FORM3 f3=new FORM3();                 ///Call a instance of Form3
if(f3.Showdialog()==Dialogresult.OK)
{
}      

推荐答案

你可以在这里看到并解决你的问题....





http://stackoverflow.com/questions/6076526/mdi-form-in-c-sharp-parent-and-child [ ^ ]

You can see here and come out your problem....


http://stackoverflow.com/questions/6076526/mdi-form-in-c-sharp-parent-and-child[^]

最好的方法是让form2让form1去做 - 这样就不需要再了解它了。请参阅此处：在两种表格之间传递信息，第3部分：儿童与儿童 [ ^ ] - 它没有直接相关性，因为它假定form2和form3已经存在，但它显示了一般原则。

The best way is to have form2 ask form1 to do it - that way it doesn't need to know any more about it. See here: Transferring information between two forms, Part 3: Child to Child[^] - it's not directly relevant, since it assumes that the form2 and form3 exist already, but it shows the general principle.

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