[UWP]更改用CameraCaptureUI录制的视频的名称[C ++] [英] [UWP]Change the name of a video recorded with CameraCaptureUI [C++]

问题描述

I我正在使用C ++和XAML开发UI应用程序。在执行中有一点我使用CameraCaptureUI来
录制视频。代码如下所示：

 CameraCaptureUI ^ dialog = ref new CameraCaptureUI（）; 
 dialog-> VideoSettings-> Format = CameraCaptureUIVideoFormat :: Mp4; 
 
 
 
 
 concurrency :: task< StorageFile ^>（dialog-> CaptureFileAsync（CameraCaptureUIMode :: Video））。then（[this]（StorageFile） ^ file）{
 if（file！= nullptr）{
 
 concurrency :: task< Streams :: IRandomAccessStream ^>（file-> OpenAsync（FileAccessMode :: Read））。然后（[this]（Streams :: IRandomAccessStream ^ stream）{
 // CapturedVideo-> SetSource（stream，" video / mp4"）; 
 logger-> Text =" grabando" ; 
}）; 
 
 Windows :: Foundation :: Collections :: IPropertySet ^ appSettings = ApplicationData :: Current-> LocalSettings->值; 
 
 appSettings->插入（" CaptureVideo"，PropertyValue :: CreateString（file-> Path））; 
 
}）; 

这就是我所做的一切我录制了一个视频，它总是有"CCapture（X）"。作为一个名字，X是一个创建独特的
名称。我尝试使用CopyAsync函数复制文件：

 create_task（StorageLibrary :: GetLibraryAsync（KnownLibraryId :: Videos））
 .then（[this]（StorageLibrary ^ videosLibrary）
 {
 Windows :: Storage :: StorageFolder ^ _videoLib = videosLibrary-> SaveFolder; 
 if（_videoLib == nullptr）
 {
 //在这种情况下回退到本地应用程序存储，因为图片库不可用
 _videoLib = ApplicationData :: Current-> LocalFolder; 
} 
 
 
}）; 
 
 // EtiquetaVid是早先创建的字符串
 file-> CopyAsync（_videoLib，stringToPlatformString（etiquetaVid），NameCollisionOption :: GenerateUniqueName）; 

但是我的视频库中没有任何内容，并且没有任何错误可以指导我。

我的问题是：如何控制输出视频的名称？我搜索了文档和论坛，但似乎无法找到解决方案。

解决方案

嗨Carlos Her，

>>

我该怎么办？控制输出视频的名称？

由于您已经在StorageFile对象中获取了视频，因此您可以使用
直接重命名该视频
StorageFile.RenameAsync方法。

最好的问候，

罗伊

I am using C++ and XAML to develop an UI application. There is a point in the execution that I use a CameraCaptureUI to record a video. The code looks like this:

CameraCaptureUI^ dialog = ref new CameraCaptureUI();
    dialog->VideoSettings->Format = CameraCaptureUIVideoFormat::Mp4;




    concurrency::task<StorageFile^>(dialog->CaptureFileAsync(CameraCaptureUIMode::Video)).then([this](StorageFile^ file) {
        if (file != nullptr) {

            concurrency::task<Streams::IRandomAccessStream^>(file->OpenAsync(FileAccessMode::Read)).then([this](Streams::IRandomAccessStream^ stream) {
                //  CapturedVideo->SetSource(stream, "video/mp4");
                logger->Text = "grabando";
            });

            Windows::Foundation::Collections::IPropertySet^ appSettings = ApplicationData::Current->LocalSettings->Values;

            appSettings->Insert("CaptureVideo", PropertyValue::CreateString(file->Path));

     });

This is all I do to it, once I record a video, it always has "CCapture(X)" as a name, being X a away to create unique names. I tried copying the file by using CopyAsync function:

create_task(StorageLibrary::GetLibraryAsync(KnownLibraryId::Videos))
                .then([this](StorageLibrary^ videosLibrary)
            {
                Windows::Storage::StorageFolder^ _videoLib = videosLibrary->SaveFolder;
                if (_videoLib == nullptr)
                {
                    // In this case fall back to the local app storage since the Pictures Library is not available
                    _videoLib = ApplicationData::Current->LocalFolder;
                }


            });

            //EtiquetaVid is a string created earlier
            file->CopyAsync(_videoLib, stringToPlatformString(etiquetaVid), NameCollisionOption::GenerateUniqueName);

But I nothing appeared on my video library and there were no errors to guide me.

My question is: How can I control the name of the output video? I've searched through the documentation and forums but I can't seem to find a solution.

解决方案

Hi Carlos Her,

>> How can I control the name of the output video?

Since you have already get the video in a StorageFile Object, you could directly rename it using StorageFile.RenameAsync Method.

Best regards,

Roy

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