三角形的区域，利用苍鹭的配方 [英] area of a triangle, making use of the heron's formula

问题描述

嘿，

i初学者，我被要求制作一个程序，利用苍鹭的公式，以及一些关于找到三角形区域的函数的知识。我做了，但有一个问题，我无法弄清楚。它是它给出了错误的答案!!!。

i不知道为什么。我经历了该计划的每一步，没有发现任何缺陷。请帮助我找到我程序中的缺陷。

更具体一点： -

实际上我编程的方式是这样的，当我放入3三角形的两边，它通过利用苍鹭的公式来计算三角形的面积，当我给出三边的值时，它计算并给出错误的答案（错误）区域）!!

这里是代码

  int  ss =（se + SR + ST）/ 2; 
  int  ree =  0 ; 
 ree = sqrt（（ss-se）*（ss-sr）*（ss-st））; 
  return  ree; 
 

- 这是整个程序的链接，以防你需要看看它。



链接

解决方案

而不是int使用float或double。如果你使用float，那么在双重使用sqrt的情况下使用sqrtf。 double给你更高的精确度。

hey,
i am beginner, i made was asked to make a program that would make use of the heron's formula, and some knowledge regarding functions to find the area of a triangle.well, i did, but there was this one problem which i was not able to figure out.here it is " it's giving the wrong answer!!! ".
i don't know why. i went through each and every single step of the program and found no flaw. please help me find the flaw in my program.
to be a bit more specific:-
actually i programmed it in such a way that, when i give in the 3 sides of a triangle, it calculates the area of the triangle, by making use of the heron's formula,
well when i give in the values of the 3 sides, it calculates and gives the wrong answer(wrong area)!!
here's the code

int ss=(se+sr+st)/2;
int ree=0;
ree=sqrt((ss-se)*(ss-sr)*(ss-st));
return ree;

--here is the link to the whole program just in case u want to take a look at it.

link

解决方案

Instead of int use float or double. If you use float then use sqrtf, in case of double use sqrt. double gives you higher precision.

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