在MVC3中获取选定的下拉列表框值 [英] Get selected dropdown list boxvalue in MVC3

问题描述

我是MVC3的新手。我在View中创建了一个静态下拉列表框

Hi,

I am new to MVC3. I have created a static dropdown list box in View

<div class ="editor-field">
     <select name="quota" id="list">
           <option value="1">General</option>
           <option value="2">Tatkal</option>
           <option value="3">Ladies</option>
    </select>
</div>

现在我想使用ViewBag将所选值传递给另一个页面。

我不知道我需要什么东西有模型和控制器页面。



请帮忙。

Now I want to pass the selected value to another page using ViewBag.
I don't know what are the things I need to have in Model and Controller pages.

Please help.

推荐答案

我认为最好的方式哟通过使用ViewModel实现这一点。



创建两个类QuotaViewModel和配额

I think that the best way yo achieve this by using ViewModel.

Create two class QuotaViewModel and Quota

public class QuotaViewModel
{
public int QuotaId{get;set;}
public List<quota> Quotas{get;set;}
}
public class Quota
{
public int Id{get;set;}
public string Name{get;set;}
}</quota>

创建一个控制器和两个ActionResults

Create a controller and two ActionResults

public ActionResult Index()
{
var quota=new List<quota>{new Quota{Id=1,Name="Tatkal"},new Quota{Id=2,Name="Ladies"}};

return View(quota);
}
</quota>

创建一个动作以获取下面的下拉列表值

Create a action for get the value of dropdownlist like below

public ActionResult Create(QuotaViewModel quotaViewModel)
{
//you get the selected id while clicking the button
int selectedId=quotaViewModel.QuotaId
return View();
}

创建一个应返回模型的视图QuotaViewModel

Create a view which should return the model QuotaViewModel

@model QuotaViewModel
@{
}
@using(Html.BeginForm("YourControllerName","Create", FormMethod.Post)){
@Html.DropDownListFor(m => m.QuotaId, Model.Quotas)
<input type="submit" value="click here"/>
}

希望这有帮助

Hope this helps

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