我如何打开一个弹出窗口并从Winfrom应用程序中选择一个值 [英] How I open a popup and select a value from This in Winfrom application

问题描述

你好专家



我有一个Windows窗体应用程序我想打开弹出窗口点击一个按钮，弹出窗口中有一个项目列表名称（例如）。然后在弹出窗口中单击一个项目名称，它将此项目名称返回到父窗口的文本框。我该怎么做...





请帮助......

解决方案

检查这些..

http：//www.asp。 net / ajaxLibrary / AjaxControlToolkitSampleSite / ModalPopup / ModalPopup.aspx [ ^ ]

http://www.howtosolutions.net/2013/01/creating-a-new-popup-window-in-winform-using-csharp/#.Ufe-XKx27Ek [ ^ ]

http： //dev.wavemaker.com/wiki/bin/wmjsref_6.4/PopupMen uButton [ ^ ]

Hello Experts

I have a windows form application Where I want to open popup on click a button where popup have a list of items Name(for example). And then click to a Item name in popup window,It return this Item Name to parent's window's Textbox . How Can i do this...


Please Help...

解决方案

Check these..
http://www.asp.net/ajaxLibrary/AjaxControlToolkitSampleSite/ModalPopup/ModalPopup.aspx[^]
http://www.howtosolutions.net/2013/01/creating-a-new-popup-window-in-winform-using-csharp/#.Ufe-XKx27Ek[^]
http://dev.wavemaker.com/wiki/bin/wmjsref_6.4/PopupMenuButton[^]

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