xml序列化 - 动态更改元素名称 [英] xml serialization - dynamically change element name

问题描述

我正在使用xmlserialization，创建了一些类，但对于一个节点我想要xml为

 <   AliasNames  >  
 <   AliasGivenName1  >  Joe <   / AliasGivenName1  >  
 <   AliasMiddleName1  >  <   / AliasMiddleName1  >  
 <   AliasFamilyName1  >  Doe <   / Alias FamilyName1  >  
 <   AliasGivenName2  >  Jerry <   / AliasGivenName2  >  
 <   AliasMiddleName2  >  B <   / AliasMiddleName2  >  
 <   AliasFamilyName2  >  Doe <   / AliasFamilyName2  >  
 <   AliasGivenName3  >  Jim <   / AliasGivenName3  >  
 <   AliasMiddleName3  >  C <   / AliasMiddleName3  >  
 <   AliasFamilyName3  >  Doe <   / AliasFamilyName3  >  
 
 
 <   / AliasNames  >  

这包含添加到xml节点的索引。



如何实现这一目标，请帮忙。



提前致谢。

解决方案

您应该重新考虑序列化数据的方式，以获得更像xml的内容：

 <   aliasnames  >  
 <   aliasname  >  
 <  给定 >  Joe <   / given  >  
 <   middle  >  <   / middle  >  
 <   family  >  Doe <   / family  >  
 <   / aliasname  >  
 <   aliasname  >  
 <  给定 >  Jerry <  < span class =code-leadattribute> / given  >  
 <   middle  >  B <  < span class =code-leadattribute> / middle  >  
 <   family  >  Doe <   / family  >  
 <   / aliasname  >  
 <   aliasname  >  
 <  给定 >  Jim < span class =code-keyword><   / given  >  
 <   middle  >  C < span class =code-keyword><   / middle  >  
 <  系列 >  Doe <   / family  >  
 <   / aliasname  >  
 <   / aliasnames  < span class =code-keyword>>  

这可以使用具有Given，Middle和Family属性的AliasName类数组来完成。 />


如果你不能改变xml格式，你应该自己使用XmlDocument：

 XmlDocument xml = < span class =code-keyword> new  XmlDocument（）; 
 XmlElement eltRoot = xml.CreateElement（  AliasNames）; 
 xml.AppendChild（eltRoot）; 
  for （ int  i =  1 ; i< = arrayOfNames.Length（）; ++ i）
 {
 XmlElement elt = xml.CreateElement（  AliasGivenName + I）; 
 elt.InnertText = arrayOfNames [i] .GivenName; 
 eltRoot.AppendChild（elt）; 
 elt = xml.CreateElement（  AliasMiddleName + i）; 
 elt.InnerText = arrayOfNames [i] .MiddleName; 
 eltRoot.AppendChild（elt）; 
 elt = xml.CreateElement（  AliasFamilyName + i）; 
 elt.InnertText = arrayOfNames [i] .FamilyName; 
 eltRoot.AppendChild（elt）; 
} 
 xml.Save（filename）; 

不要这样做。请改为：

 <   aliasnames  >  
 <   aliasname  >  
 <   aliasgivenname  >  Joe <   / aliasgivenname  >  
 <   aliasmiddlename  >  <   / aliasmiddlename  >  
 <   aliasfamilyname  >  Doe <   / aliasfamilyname  >  
 <   / aliasname  >  
 <   aliasname  >  
 <   aliasgivenname  >  Jerry <   / aliasgivenname  >  
 <   aliasmiddlename  >  B <   / aliasmiddlename  >  
 <   aliasfamilyname  >  Doe <   / aliasfamilyname  >  
 <   / aliasname  >  
 <   aliasname  >  
 <   aliasgivenname  >  Jim <   / aliasgivenname  >  
 <   aliasmiddlename  >  C <   / aliasmiddlename  >  
 <   aliasfamilyname  >  Doe <   / aliasfamilyname  >  
 <   / aliasname  >  
 <   / aliasnames  < span class =code-keyword>>  

感谢您的回复。我使用xml序列化程序将您提供的代码与我的代码集成在一起。

  //  函数返回带有值的XmlDocument  
  public  XmlDocument GetAliasNames（）
 {
 XmlDocument xml =  new  XmlDocument（）; 
 XmlElement eltRoot = xml.CreateElement（  AliasNames）; 
 xml.AppendChild（eltRoot）; 
  for （ int  i =  1 ; i< = arrayOfNames.Length（）; ++ i）
 {
 XmlElement elt = xml.CreateElement（  AliasGivenName + I）; 
 elt.InnertText = arrayOfNames [i] .GivenName; 
 eltRoot.AppendChild（elt）; 
 elt = xml.CreateElement（  AliasMiddleName + i）; 
 elt.InnerText = arrayOfNames [i] .MiddleName; 
 eltRoot.AppendChild（elt）; 
 elt = xml.CreateElement（  AliasFamilyName + i）; 
 elt.InnertText = arrayOfNames [i] .FamilyName; 
 eltRoot.AppendChild（elt）; 
} 
  return  xml; 
} 

我上课了;

  public   class  _PersonalData 
 {
  public  _PersonName PersonName =  new  _PersonName（）; 
  public  _DemographicDetail DemographicDetail =  new  _DemographicDetail（）; 
 
  public  XmlDocument AliasNames { get ;  set ; } 
} 

我将值设置为;

 PersonalData.AliasNames = GetAliasNames（）; 

和my xml为;

 <   BackgroundSearchPackage  >  
 <   PersonalData  >  
 <   PersonName  >  
 <   GivenName  >  pritam <   / GivenName  >  
 <  中间名 >  ravi <   / MiddleName  >  
 <   FamilyName  >  Ajmire <   / FamilyName  >  
 <   / PersonName  >  
 <   DemographicDetail  >  
 <   Ssn  >  234523dsf <   / Ssn  >  
 <   DateOfBirth  >  14/23/1990 < ;   / DateOfBirth  >  
 <  种族 >  dsf < ;   / Race  >  
 <   GenderCode  >  M < ;   / GenderCode  >  
 <   / DemographicDetail  >  
 <   AliasNames  >  
 <   AliasNames  >  
 <   AliasGivenName1  >  GN1 <   / AliasGivenName1  >  
 <   AliasMiddleName1  >  MN1 <   / AliasMiddleName1  >  
 <   AliasFamilyName1  >  FN1 <   / AliasFamilyName1  >  
  <   / AliasNames  >  
 <   / AliasNames  >  
 <   / PersonalData  >  
 <   / BackgroundSearchPackage  >  

I am using xmlserialization, created some classes, but for one node I want xml as

<AliasNames>
<AliasGivenName1>Joe</AliasGivenName1>
<AliasMiddleName1>A</AliasMiddleName1>
<AliasFamilyName1>Doe</AliasFamilyName1>
<AliasGivenName2>Jerry</AliasGivenName2>
<AliasMiddleName2>B</AliasMiddleName2>
<AliasFamilyName2>Doe</AliasFamilyName2>
<AliasGivenName3>Jim</AliasGivenName3>
<AliasMiddleName3>C</AliasMiddleName3>
<AliasFamilyName3>Doe</AliasFamilyName3>


</AliasNames>

This contains index added to xml node.

how can I accomplish this, please help.

Thanks in advance.

解决方案

You should reconsider the way you are serialising your data to have something more "xml-like":

<aliasnames>
  <aliasname>
    <given>Joe</given>
    <middle>A</middle>
    <family>Doe</family>
  </aliasname>
  <aliasname>
    <given>Jerry</given>
    <middle>B</middle>
    <family>Doe</family>
  </aliasname>
  <aliasname>
    <given>Jim</given>
    <middle>C</middle>
    <family>Doe</family>
  </aliasname>
</aliasnames>

This can be done using an array of AliasName class with Given, Middle and Family properties.

If you cannot change the xml format, you should use the XmlDocument by yourself:

XmlDocument xml = new XmlDocument();
XmlElement eltRoot = xml.CreateElement("AliasNames");
xml.AppendChild(eltRoot);
for(int i=1; i<=arrayOfNames.Length(); ++i)
{
  XmlElement elt = xml.CreateElement("AliasGivenName"+i);
  elt.InnertText = arrayOfNames[i].GivenName;
  eltRoot.AppendChild(elt);
  elt = xml.CreateElement("AliasMiddleName"+i);
  elt.InnerText = arrayOfNames[i].MiddleName;
  eltRoot.AppendChild(elt);
  elt = xml.CreateElement("AliasFamilyName"+i);
  elt.InnertText = arrayOfNames[i].FamilyName;
  eltRoot.AppendChild(elt);
}
xml.Save(filename);

Don't do it that way. Do this instead:

<aliasnames>
 <aliasname>
   <aliasgivenname>Joe</aliasgivenname>
   <aliasmiddlename>A</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
 <aliasname>
   <aliasgivenname>Jerry</aliasgivenname>
   <aliasmiddlename>B</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
 <aliasname>
   <aliasgivenname>Jim</aliasgivenname>
   <aliasmiddlename>C</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
</aliasnames>

Thanks for your response. I have integrated code supplied by you with my code using xml serializer.

// function returns XmlDocument with values
public XmlDocument GetAliasNames()
{
  XmlDocument xml = new XmlDocument();
  XmlElement eltRoot = xml.CreateElement("AliasNames");
  xml.AppendChild(eltRoot);
  for(int i=1; i<=arrayOfNames.Length(); ++i)
  {
    XmlElement elt = xml.CreateElement("AliasGivenName"+i);
    elt.InnertText = arrayOfNames[i].GivenName;
    eltRoot.AppendChild(elt);
    elt = xml.CreateElement("AliasMiddleName"+i);
    elt.InnerText = arrayOfNames[i].MiddleName;
    eltRoot.AppendChild(elt);
    elt = xml.CreateElement("AliasFamilyName"+i);
    elt.InnertText = arrayOfNames[i].FamilyName;
    eltRoot.AppendChild(elt);
  }
  return xml;
}

I had a class as;

public class _PersonalData
{
    public _PersonName PersonName = new _PersonName();
    public _DemographicDetail DemographicDetail = new _DemographicDetail();

    public XmlDocument AliasNames { get; set; }
}

and I set values as;

PersonalData.AliasNames = GetAliasNames();

and my xml is as;

<BackgroundSearchPackage>
<PersonalData>
<PersonName>
<GivenName>pritam</GivenName>
<MiddleName>ravi</MiddleName>
<FamilyName>Ajmire</FamilyName>
</PersonName>
<DemographicDetail>
<Ssn>234523dsf</Ssn>
<DateOfBirth>14/23/1990</DateOfBirth>
<Race>dsf</Race>
<GenderCode>M</GenderCode>
</DemographicDetail>
<AliasNames>
<AliasNames>
<AliasGivenName1>GN1</AliasGivenName1>
<AliasMiddleName1>MN1</AliasMiddleName1>
<AliasFamilyName1>FN1</AliasFamilyName1>
</AliasNames>
</AliasNames>
</PersonalData>
</BackgroundSearchPackage>

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