获取当前进程的句柄时CreateFile失败 [英] CreateFile Failing When Getting Handle to Current Process

问题描述

char CurrentPath[MAX_PATH] = {0};
GetModuleFileName(NULL,CurrentPath,MAX_PATH);
char BaseNameA[MAX_PATH] = {0};
GetBaseNameFromPath(CurrentPath,BaseNameA);
if(hFile==NULL)
{
    hFile = CreateFile(CurrentPath,GENERIC_READ,0,NULL,OPEN_EXISTING,FILE_ATTRIBUTE_NORMAL,NULL);
    if(hFile==INVALID_HANDLE_VALUE)
        MessageBox(0,"hFile Failed!",0,0);
}

您好！



上面的代码是随机失败的（有时它完美地运行，有时它会报告hFile Failed！）。我不太明白为什么它有时会失败。



也许我应该使用C库来打开当前进程的文件？



也许有人知道更可靠的解决方案？



我想要做的就是打开当前进程的本地文件我我在。



谢谢！

Hello!

The code above is failing randomly (sometimes it works perfectly, other times it reports "hFile Failed!"). I don't quite understand why it fails at times.

Perhaps I should use C-libraries for opening the current process's file?

Perhaps someone knows a more reliable solution?

Again all I'm trying to do is open the local file of the current process I'm in.

Thank you!

推荐答案

尝试使用 FILE_SHARE_READ | FILE_SHARE_WRITE 作为第3个参数。

Try using FILE_SHARE_READ|FILE_SHARE_WRITE as the 3rd parameter.

这篇关于获取当前进程的句柄时CreateFile失败的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！