读取XML文件并在C#中将其写入.txt格式 [英] Reading XML File and Writing it to .txt format in C#

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本文介绍了读取XML文件并在C#中将其写入.txt格式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

XML文件的当前输出当我运行我的代码时 - fanemlname0772569984ac@gs.com7/17/2013 9:04:48 AM

所需输出从XML文件当我运行我的代码 - fname,lname,0772569984,ac @ gs.com,7/17/2013,9:04:48 AM



帮帮我们谢谢!!!!

这是我的代码

我使用的XML文件位于代码后面

Current Output From the XML file When i run my code - fanemlname0772569984ac@gs.com7/17/2013 9:04:48 AM
Required Output From the XML file When i run my code - fname,lname,0772569984,ac@gs.com,7/17/2013, 9:04:48 AM

Help me out guys thanks!!!!
This is my Code
XML File i used is below after the code

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Xml;
using System.IO;


namespace ReadXMLfromFile
{

    class Class1
    {
        static void Main(string[] args)
        {
            XmlTextReader reader = new XmlTextReader("Visitors (2).xml");
            while (reader.Read())
            {
                switch (reader.NodeType)
                {
                    case XmlNodeType.Element: 
                        Console.WriteLine(reader.Value);

                        break;
                    case XmlNodeType.Text: 
                        Console.WriteLine(reader.Value);
                        break;
                }
            }
            Console.ReadLine();
            string onlyContent = string.Empty;

            XmlDocument xdoc = new XmlDocument();
            xdoc.Load(@"C:\Users\afshandc\Desktop\ConsoleApplication1\ConsoleApplication1\Visitors (2).xml");

            var visitors = xdoc.SelectNodes("Visitors/Visitor");
            for (int i = 0; i < visitors.Count; i++)
            {

                onlyContent += string.Format("\n", i);

                foreach (XmlNode node in visitors[i].ChildNodes)
                    onlyContent += string.Format("{0}", node.InnerText);
            }

            File.WriteAllText(@"C:\Users\afshandc\Desktop\ConsoleApplication1\ConsoleApplication1\Written XML.txt", onlyContent);
        }
    }

}










<Visitors>
  <Visitor>
    <FirstName>fanem</FirstName>
    <LastName>lname</LastName>
    <ContactNo>0772569984</ContactNo>
    <Email>ac@gs.com</Email>
    <Date>7/17/2013 9:04:48 AM</Date>
  </Visitor>
  <Visitor>
    <FirstName>fname22</FirstName>
    <LastName>Lname234</LastName>
    <ContactNo>1234567890</ContactNo>
    <Email>visitorgmail.com</Email>
    <Date>7/17/2013 9:11:02 AM</Date>
  </Visitor>

推荐答案

var visitor = xdoc.SelectNodes(访客/访客);

for(int i = 0;我< visitors.Count; i ++)

{

foreach(访问者[i] .ChildNodes中的XmlNode节点)

onlyContent + = string.Format({0} ,,node.InnerText);

onlyContent = onlyContent.TrimEnd(',');

onlyContent + = string.Format({0},Environment。 NewLine);

}



这也适用于您的要求。

只是想发布。

干杯

BS
var visitors = xdoc.SelectNodes("Visitors/Visitor");
for (int i = 0; i < visitors.Count; i++)
{
foreach (XmlNode node in visitors[i].ChildNodes)
onlyContent += string.Format("{0},", node.InnerText);
onlyContent = onlyContent.TrimEnd(',');
onlyContent += string.Format("{0}", Environment.NewLine);
}

This also works for your requirement.
Just thought of posting.
Cheers
B.S


afshandc你重新发布



afshandc you reposted

namespace ReadXMLfromFile
{
    class Class1
    {
        static void Main(string[] args)
        {
            string onlyContent = string.Empty;

            XmlDocument xdoc = new XmlDocument();
            xdoc.Load(@"C:\Users\afshandc\Desktop\ConsoleApplication1\ConsoleApplication1\Visitors (2).xml");

            var visitors = xdoc.SelectNodes("Visitors/Visitor");
            for (int i = 0; i < visitors.Count; i++)
            {
                onlyContent += string.Format("\n", i);

                foreach (XmlNode node in visitors[i].ChildNodes)
                    onlyContent += string.Format("{0},", node.InnerText);
            }

            File.WriteAllText(@"C:\Users\afshandc\Desktop\ConsoleApplication1\ConsoleApplication1\Written XML.txt", onlyContent);
        }
    }

}


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