RxJava和改造 - 与接收的第一个步骤 [英] RxJava and Retrofit - first steps with Rx

问题描述

使用RxJava（不Retrolambda），我愿做一些API调用，完成我的数据吧。我的不完整的对象是一个TvShow'与对象'季节的列表。这个季节是空的，我需要用情节来完成它。

With RxJava (without Retrolambda), I would like to do some API calls and complete my data with it. My incomplete object is a 'TvShow' with a list of object 'Season'. This 'Season' is empty and I need to complete it with episodes.

Observable<TvShow> getDataTVShow(long idTvShow)
//get TvShow with empty seasons (except season number)

Observable<Season> getDataSeason(long idTvShow, int seasonNumber); 
//get one complete season with episodes

所以我想：

• 获取我的'TvShow'对象的（OK）


• 迭代赛季（名单＆LT; \\赛季>）从我的'TvShow对象和每个季节做一个API调用，让我的赛季完全结束，然后在列表更新我的'老'的季节。


• 然后，一旦我们有我们所需要的，持久化数据到数据库中（用户部分）

到现在为止，我只有：

Observable<TvShow> = apiService.getDataTvShow(idTvShow)

我现在需要遍历赛季，我试图用运算符'地图'，从'TvShow'对象切换到我的季节名单（tvShow.getSeasons（）），但我不知道是在好办法。除了这一点，我知道'doOnNext'将被用于更新我的'老'的季节，仅此而已。

I need now to iterate over seasons, I tried to use operator 'map' to switch from 'TvShow' object to my list of seasons (tvShow.getSeasons()) but I'm not sure to be in the good way. Beside that, I know 'doOnNext' will be used to update my 'old' season, that's it.

我试着用这个很好的例子的工作：<一href=\"http://stackoverflow.com/questions/27693425/handling-lists-with-rxjava-and-retrofit-in-android\">Handling与RxJava并列出改造android中，但我还是坚持：（

I tried to work with this good example: Handling lists with RxJava and Retrofit in android but I'm still stuck :(

如果你能帮助我解决这个问题，这将是巨大的：）

If you can help me solve this problem, it would be great :)

推荐答案

例如，你有两个观测值：

For example you have two observables:

Observable<Season> getSeason(int id)
Observable<TvShow> getTvShow(String id)

如何负载TvShow然后加载每个赛季，并填写TvShow：

How load TvShow then load each Season and fill TvShow:

  Observable<TvShow> getFilledTvShow = getTvShow("123")
      .flatMap(tvShow ->
              //make stream observable from seasons
              Observable.from(tvShow.seasons)
                  //load each season from network
                  .flatMap(season -> getSeason(season.id))
                      //then collect all results to ArrayList
                  .collect(() -> new ArrayList<Season>(),
                      (seasons, filledSeason) -> seasons.add(filledSeason))
                      //finally fill tvShow and return it
                  .map(filledSeasons_ -> {
                     tvShow.seasons = filledSeasons_;
                     return tvShow;
                  })
      );

请注意。我不知道，这是一个最好的解决办法，因为我不是很用RX还没有经历;

Note. I am not sure that it's a best solution, because I'm not very experienced with rx yet;

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