C＃查看SFTP目录中是否存在文件 [英] C# see if files exist in SFTP directory

问题描述

您好，

我的代码如下：

 static void Main（）
 {
 string userName =" TEST" ;; 
 string password =" TEST" ;; 
 string ftpURL =" sftp.iehp.org//Directory1//Director2 // * FileBLahBlah * .csv" ;; 
 
 try 
 {
 FtpWebRequest ftpRequest =（FtpWebRequest）WebRequest.Create（ftpURL）; 
 ftpRequest.Method = WebRequestMethods.Ftp.DownloadFile; 
 ftpRequest.Credentials = new NetworkCredential（userName，password）; 
 
使用（FtpWebResponse ftpResponse =（FtpWebResponse）ftpRequest.GetResponse（））
 {
 Console.WriteLine（" FILES EXIST"）; 
} 
} 
 catch 
 {
 Console.WriteLine（" FILES DONT EXIST"）; 
} 
 
 Console.ReadLine（）; 
 
} 

然而它似乎没有用，因为我知道该目录中有一个文件，我测试过用户名和密码，但是有一个名为TestFileBlahblah01092019.csv的文件，但它永远不会出现在控制台中。"文件存在"，我知道i
我错过了这么简单的东西......任何帮助：（

解决方案

查看异常可能会有所帮助：

 catch （例外e）
 {
 Console.WriteLine（e）; 
} 

Hello,

i have the following code below:

        static void Main()
        {
            string userName = "TEST";
            string password = "TEST";
            string ftpURL = "sftp.iehp.org//Directory1//Director2//*FileBLahBlah*.csv";
            
            try
            {
                FtpWebRequest ftpRequest = (FtpWebRequest)WebRequest.Create(ftpURL);
                ftpRequest.Method = WebRequestMethods.Ftp.DownloadFile;
                ftpRequest.Credentials = new NetworkCredential(userName, password);

                using (FtpWebResponse ftpResponse = (FtpWebResponse)ftpRequest.GetResponse())
                {
                    Console.WriteLine("FILES EXIST");
                }
            }
            catch
            {
                Console.WriteLine("FILES DONT EXIST");
            }

            Console.ReadLine();

        }

however it doesnt seem to work because i know there is a file in that directory, i tested the username and password, however there is a file called TestFileBlahblah01092019.csv however it never shows up in the console.. "Files Exist", i know i am missing something so simple... any help :(

解决方案

Maybe it would be helpful to see the exception:

            catch(Exception e)
            {
                Console.WriteLine(e);
            }

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