C＃中ShowDialog（）方法的问题。 [英] Problem with ShowDialog() method in C#.

问题描述

我想将表单调用到另一个表单，但我希望调用表单显示为对话框（不调整大小）。我将参数传递给我的new_customer表单的构造函数。

所以我的代码是： -

I want to call a form to another form, but I want the calling form shows like dialog box(not resizing). I passing parameter to my new_customer form's constructor.
so My code is :-

new_customer NC = new new_customer(null);
            NC.ShowDialog();

我的new_customer表单构造函数： -

My new_customer form constructor :-

public new_customer(string formType="save")
       {
           InitializeComponent();
           DC = new Data_Conn(Application.StartupPath);
           DC1 = new Data_Conn(Application.StartupPath);
           paraModi = formType;
       }

问题是当我从另一个表单调用new_customer表单时，它的构造函数不执行，这就是我使用该变量时出错的原因：

Problem is when I call new_customer form from another form, its constructor doesn't execute,that's why I get an error when I use that variable :

Object reference not set to an instance of an object.

谢谢在高级..

thanks In advanced ..

推荐答案

你好，



你正在向第二个表单发送null尝试：

hello,

You are sending null to the second form try:

new_customer NC = new new_customer("save");//the string that you need to sent
            NC.ShowDialog();

：

on the new_customer form :

  public partial class new_customer: Form
    {
string formType;

public new_customer(string formType)//formType=save that you have sent
       {
           this.formType=formType;
           InitializeComponent();
           DC = new Data_Conn(Application.StartupPath);
           DC1 = new Data_Conn(Application.StartupPath);
           paraModi = formType;
       };
    }

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