如何改变初始视图？ [英] How to change intital view?

问题描述

如何更改图像的初始视图？

图像是全景图像，现在初始视图粘贴在视口的顶部。

我想将初始视图向下移动，使图像居中到视口，以便更方便地放大图片。

提前感谢，山姆

How can I change the initial view of my image?

The image is panoramic, and right now the initial view is stuck to the top of the viewport.

I would like to move the initial view down, to center the image to the viewport, for more convenient zooming into the picture.

thanks in advance,
Sam

推荐答案

您在page.xaml.cs文件中进行了更改。

ViewportWidth
图像区域的宽度显示。该值以逻辑坐标表示。例如，值1显示整个图像（无缩放），值0.5为200％放大，值0完全缩放（用户根本无法看到图像）。大于1的值将从图像缩小。例如，值为2意味着图像将占用 MultiScaleSubImage 控制区域（50％缩放）的一半大小。


ViewportOrigin
X（-0.02456985）=要显示的图像的矩形区域的左侧坐标。该点的坐标相对于显示的图像宽度在本地坐标（0-1）中。
Y（-0.35426895）=要显示的图像的矩形区域的顶部坐标。点的坐标相对于显示的图像宽度在本地坐标（0-1）中。

You make changes in the page.xaml.cs file.

ViewportWidth
The width of the area of the image displayed. This value is in logical coordinates. For example, a value of 1 displays the entire image (no zoom), a value of 0.5 is 200% zoomed in, and a value of 0 is completely zoomed (user cannot see the image at all). A value above 1 is zooming out from the image. For example, a value of 2 means that the image will take up half the size of the MultiScaleSubImage control area (50% zoom).


The ViewportOrigin
X (-0.02456985) =  The left coordinate of the rectangular area of the image to be displayed. The coordinates of the point are in local coordinates (0-1) relative to the displayed image width.
Y (-0.35426895) = The top coordinate of the rectangular area of the image to be displayed. The coordinates of the point are in local coordinates (0-1) relative to the displayed image width.

        void msi_ImageOpenSucceeded(object sender, RoutedEventArgs e)
        {
            this.msi.ViewportWidth = 0.5;
            this.msi.ViewportOrigin = new Point(-0.02456985, -0.035426895);
            ZoomFactor = 0.5;
        }

进一步了解：

http://msdn.microsoft.com/en-us/library/cc645050(VS.95）。 aspx

See further:

http://msdn.microsoft.com/en-us/library/cc645050(VS.95).aspx

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