验证两个日期 [英] validation two date

问题描述

hi
如何验证第一个日期之类的两个日期少于第二个日期

感谢

hi how to validate two date like first date is less then second date
thanks

推荐答案

Declare @D1 datetime, @D2 datetime
set @D1 = '2013-07-05' --yyyy-mm-dd
set @D2 = '2013-07-09' --yyyy-mm-dd
select
    case
        when @D1 = @D2 then 'equal dates'
        when @D1 < @D2 then 'first date is less then second date'
        else 'Second date is less then first date'
    end

快乐编码！

：）

Happy Coding!
:)

请参阅此处。太简单了。



DateTime.Compare方法 [ ^ ]



问候......：笑：

Refer to this. Its too simple.

DateTime.Compare Method[^]

Regards.. :laugh:

function checkDate()
{
    var fromDate=document.getElementById("<%=tcstartdate.ClientID%>").value;
    var toDate=document.getElementById("<%=tcenddate.ClientID%>").value;
    var cataloguename=document.getElementById("<%=txtcataloguename.ClientID%>").value;
    var desc=document.getElementById("<%=txtdescription.ClientID%>").value;

    if(cataloguename.trim() == "")
    {
        alert("Please Enter Special name");
        document.getElementById("<%=txtcataloguename.ClientID%>").focus();
        return false;
    }
    if(fromDate == "")
    {
        alert("Please Enter Special start date");
        document.getElementById("<%=tcstartdate.ClientID%>").focus();
        return false;
    }
    if(toDate == "")
    {
        alert("Please Select Special End date");
        document.getElementById("<%=tcenddate.ClientID%>").focus();
        return false;
    }
   // alert(fromDate);
   // alert(toDate);

    var record_day1=fromDate.split("/");
    var sum1=record_day1[1]+'/'+record_day1[0]+'/'+record_day1[2];
    var record_day2=toDate.split("/");
    var sum2=record_day2[1]+'/'+record_day2[0]+'/'+record_day2[2];
    var record1 = new Date(sum1);
    var record2 = new Date(sum2);
    var d = new Date();
    var ddd =d.getMonth()+ 1 +'/'+d.getDate()+'/'+d.getFullYear();
    var dd=new  Date(ddd);
    if(record2 < record1)
    {
            alert("Invalid Date ! Please try again");
              document.getElementById("<%=tcstartdate.ClientID%>").focus();
            return false;
    }
    if(record2 < dd)
    {
          alert("Invalid Date ! Please try again");
             document.getElementById("<%=tcstartdate.ClientID%>").focus();
            return false;
    }
//    if(desc.trim() == "")
//    {
//        alert("Please enter description ");
//        document.getElementById("<%=txtdescription.ClientID%>").focus();
//        return false;
//    }

     var inputs = [];
     var i,c=0;
     grid=document.getElementById("<%=gridCatalogue.ClientID %>");
     inputs = document.getElementById("<%=gridCatalogue.ClientID %>").getElementsByTagName("input");
      var input=document.getElementsByTagName("input");
     for (i=0;i<grid.rows.length-1;i++)
       if(inputs[4*i].value!="")
       {
           c++;
        }
       if(c==0)
       {
            alert("Please enter atleast one product");
            return false;
       }
            //alert('came');
            var input=document.getElementsByTagName("input");
            var sample,hidid;
            for(var i=0;i<input.length;i++)
            {
                //alert(input[i].type);
                if(input[i].type=="hidden")
                    hidid=document.getElementById(input[i].id).value;
                if(input[i].type=="text")
                {
                    if(input[i].id.indexof("txtprice")>0)
                    {
                        sample=document.getElementById(input[i].id).value;
                        if(isnan(parseint(sample)) && !isnan(parseint(hidid)))
                        {
                            alert("Please enter price");
                            document.getElementById(input[i].id).focus();
                                return false;
                            }
                        else if(!isnan(parseint(hidid)))
                        {
                            var isfound = /^(?!^0*

这篇关于验证两个日期的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！