如何获取许可证密钥？ [英] How to get the license key?

问题描述

如何在Windows应用程序中获取许可证密钥。我需要2PHXF-9PBDW-D3WWY-CPDKD-XG87V这种格式。请帮帮我......

i试过这个代码

  private   void  btn_License_Click（ object  sender， EventArgs e）
 {
 Random ran =  new  Random（）; 
 textBox1.Text =   + ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+   _  + ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ，  9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+   _ + ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ） + ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）+ ran.Next（ 0 ， 9 ）; 
} 

解决方案

我的解决方案是：



私人static Random rd = new Random（（int）DateTime.Now.Ticks）;

  private   void  btn_License_Click（ object  sender，EventArgs e）
 {
 
  string  str1 = GeneratePassword（ 5 ， 0 ）; 
  string  str2 = GeneratePassword（ 5 ， 0 ）; 
  string  str3 = GeneratePassword（ 5 ， 0 ）; 
  string  str4 = GeneratePassword（ 5 ， 0 ）; 
  string  str5 = GeneratePassword（ 5 ， 0 ）; 
 textBox1.Text = str1 +    -  + str2 +    -  + str3 +    -  + str4 +    -  + str5; 

} 
 
  public   static   string  GeneratePassword（ int  Lenght， int  NonAlphaNumericChars）
 {
 
  string  allowedChars =    ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789; 
  string  allowedNonAlphaNum =  ！@＃

％^&安培; *（）_- + = [{]};：其中;> | ./?\";
// Random rd = new Random（（int）DateTime.Now.Ticks）;

if （NonAlphaNumericChars > Lenght || Lenght < = 0 || NonAlphaNumericChars < 0 ）
throw new ArgumentOutOfRangeException（）;

char [] pass = new 炭 [Lenght];
int [] pos = new int < /跨度> [Lenght];
int i = 0 ，j = 0 ，temp = 0 ;
bool flag = false ;

// 随机输入字符串传递的pos数组的位置值
while （i < 长度 - 1 ）
{
j = 0 ;
flag = false ;
temp = rd.Next（ 0 ，Lenght）;

for （j = 0 ; j < 长度; j ++）
如果（temp == pos [j]）
{
flag = true ;
j =长度;
}

if （！flag）
{
pos [i] = temp;
i ++;
}
}

// 随机AlphaNumericChars
for （i = 0 ; i < Lenght - NonAlphaNumericChars; i ++）
pass [i] = allowedChars [rd.Next（ 0 ，allowedChars.Length）];

// 随机NonAlphaNumericChars
for （i = Lenght - NonAlphaNumericChars; i < Lenght; i ++）
pass [i] = allowedNonAlphaNum [rd .Next（ 0 ，allowedNonAlphaNum.Length）];

// 按照数据位置的pos数组设置排序数组值
char [] sorted = new char [Lenght];
for （i = 0 ; i < ; 长度; i ++）
sorted [i] = pass [pos [i]];

string Pass = new 串（排序）;

返回通过;
}

结果是：Y4CDQ-GAIW5-VIWE1-0EFN6-C5Z7H

这是C＃代码。只需点击按钮，您将获得不同的许可证密钥

使用System; 
使用System.Collections.Generic;使用System.ComponentModel 
; 
使用System.Data;使用System.Drawing 
; 
使用System.Linq; 
使用System.Text; 
使用System.Windows.Forms; 
 
命名空间WindowsFormsApplication1 
 {
 public partial class Form1：Form 
 {
 Random random = new Random（）; 
 public Form1（）
 {
 InitializeComponent（）; 
} 
 
 private void button1_Click（object sender，EventArgs e）
 {
 string s1 = RandomString（）; 
 string s2 = RandomString（）; 
 string s3 = RandomString（）; 
 string s4 = RandomString（）; 
 string s5 = RandomString（）; 
 textBox1.Text = s1 + - + s2 + - + s3 + - + s4 + - + s5; 
} 
 
公共字符串RandomString（）
 {
 string input =ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789; 
 StringBuilder builder = new StringBuilder（）; 
 char ch; 
 for（int i = 0; i< 5; i ++）
 {
 ch = input [random.Next（0，input.Length）]; 
 builder.Append（ch）; 
} 
返回builder.ToString（）; 
} 
} 
} 

退房并告知我们是否有帮助

How to get the license key in windows application. And i need 2PHXF-9PBDW-D3WWY-CPDKD-XG87V this format. Please help me....
i have tried this code

private void btn_License_Click(object sender, EventArgs e)
       {
           Random ran = new Random();
           textBox1.Text = "" + ran.Next(0, 9) + ran.Next(0,9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + "_" + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + "_" + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9);
       }

解决方案

My Soltion is:

private static Random rd = new Random((int)DateTime.Now.Ticks);

private void btn_License_Click(object sender, EventArgs e)
       {

           string str1 = GeneratePassword(5, 0);
           string str2 = GeneratePassword(5, 0);
           string str3 = GeneratePassword(5, 0);
           string str4 = GeneratePassword(5, 0);
           string str5 = GeneratePassword(5, 0);
           textBox1.Text = str1 + "-" + str2 + "-" + str3 + "-" + str4 + "-" + str5;

}

       public static string GeneratePassword(int Lenght, int NonAlphaNumericChars)
       {

           string allowedChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
           string allowedNonAlphaNum = "!@#

%^&*()_-+=[{]};:<>|./?"; //Random rd= new Random((int)DateTime.Now.Ticks); if (NonAlphaNumericChars > Lenght || Lenght <= 0 || NonAlphaNumericChars < 0) throw new ArgumentOutOfRangeException(); char[] pass = new char[Lenght]; int[] pos = new int[Lenght]; int i = 0, j = 0, temp = 0; bool flag = false; //Random the position values of the pos array for the string Pass while (i < Lenght - 1) { j = 0; flag = false; temp = rd.Next(0, Lenght); for (j = 0; j < Lenght; j++) if (temp == pos[j]) { flag = true; j = Lenght; } if (!flag) { pos[i] = temp; i++; } } //Random the AlphaNumericChars for (i = 0; i < Lenght - NonAlphaNumericChars; i++) pass[i] = allowedChars[rd.Next(0, allowedChars.Length)]; //Random the NonAlphaNumericChars for (i = Lenght - NonAlphaNumericChars; i < Lenght; i++) pass[i] = allowedNonAlphaNum[rd.Next(0, allowedNonAlphaNum.Length)]; //Set the sorted array values by the pos array for the rigth posistion char[] sorted = new char[Lenght]; for (i = 0; i < Lenght; i++) sorted[i] = pass[pos[i]]; string Pass = new String(sorted); return Pass; }

Result is:Y4CDQ-GAIW5-VIWE1-0EFN6-C5Z7H

Here is the C# code.Just click on button and you will get different license keys

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        Random random = new Random();
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            string s1 = RandomString();
            string s2 = RandomString();
            string s3 = RandomString();
            string s4 = RandomString();
            string s5 = RandomString();
            textBox1.Text = s1+" - "+s2+" - "+s3+" - "+s4+" - "+s5;
        }

      public string RandomString()
        {
            string input = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
            StringBuilder builder = new StringBuilder();
            char ch;
            for (int i = 0; i < 5; i++)
            {
                ch = input[random.Next(0, input.Length)];
                builder.Append(ch);
            }
            return builder.ToString();
        }
    }
}

Check out and let me know if it helped

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