Pdf附件损坏问题。 [英] Pdf attachment damaged problem.

问题描述

我在桌面上存储guid的文件，文件也用guid名称保存。

我想把这个文件作为附件发送。当我发送文件，因为它是附件与guid名称，然后它工作正常。（下面代码很好）



<前lang =c＃>附件attachResource = new 附件（Server.MapPath（ / public / _pdf / + strFILEGUID + 。pdf））;
mail.Attachments.Add（attachResource）;

但是我想发送一个不同名称的文件，所以我用过代码。

 System.IO.MemoryStream data =  new 系统.IO.MemoryStream（）; 
 System.IO.Stream str = File.OpenRead（Server.MapPath（  / public / _pdf /  + strFILEGUID +  。pdf））; 
 str.CopyTo（data）; 
 data.Seek（ 0 ，SeekOrigin.Begin）; 
  byte  [] buf =  new   byte [data.Length]; 
 data.Read（buf， 0 ，buf.Length）; 
附件attachResource =  new 附件（data，  ChangedFileName +  。pdf）; 
 mail.Attachments.Add（attachResource）; 

此代码发送文件名为'ChangedFileName.pdf'但在打开时文件说文件已损坏。我在这里没有遇到问题。任何帮助将不胜感激。

谢谢

解决方案

使用BinaryReader阅读PDF文件

 System.IO.BinaryReader bw = new BinaryReader（str）; 
 
 byte [] buf = bw.ReadBytes（（int）str.Length）; 
 

谢谢

--RA

Hi,
I am have on table which stores uploaded file with guid and file also saved with guid name.
I want to send this file as attachment. When I send file as it is in attachment with guid name then it is working fine.(below code works great)

Attachment attachResource = new Attachment(Server.MapPath("/public/_pdf/" + strFILEGUID + ".pdf"));
mail.Attachments.Add(attachResource);

But i want to send this file with some different name so i used below code.

System.IO.MemoryStream data = new System.IO.MemoryStream();
System.IO.Stream str = File.OpenRead(Server.MapPath("/public/_pdf/" + strFILEGUID  + ".pdf"));
str.CopyTo(data);
data.Seek(0, SeekOrigin.Begin);
byte[] buf = new byte[data.Length];
data.Read(buf, 0, buf.Length);
Attachment attachResource = new Attachment(data, "ChangedFileName" + ".pdf");
mail.Attachments.Add(attachResource);

This code send file with name 'ChangedFileName.pdf' but while opening file it says file is damaged. I am not getting the problem here. Any help will be appreciated.
Thanks

解决方案

Use BinaryReader to read the PDF File

System.IO.BinaryReader bw = new BinaryReader(str);

byte[] buf = bw.ReadBytes((int)str.Length);

Thanks
--RA

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