交换多维结构？ [英] Swap Mult Dimentional Structure?

问题描述

你好。



据网上其他地方说，结构可以换成如下。

Hello.

It is said elsewhere on the net that structures can be swapped as below.

typedef struct {
    int x[5];
} intarr;

int main()
{
    intarr a, b, temp;

 // Swap Structure

    temp = a;
    a    = b;
    b    = temp;

}

太棒了！



我可以为多维结构做同样的事吗？

我的结构是3维的。 m_tControlMatrix [128] [5] [9]



口也宣告m_tControlMatrixB [128] [5] [9]和m_tControlMatrixTemp [128] [5] [9]和

希望交换它们与上面的代码一样，但如果我这样做：

Great!

Can I do the same for a multidimensional structure?
My structure is 3 dimensional. m_tControlMatrix[128][5][9]

I declared also m_tControlMatrixB[128][5][9] and m_tControlMatrixTemp[128][5][9] with the
desire to swap them as with the above code but if I do:

m_tControlMatrixTemp = m_tControlMatrix;

我受到欢迎：错误C2106：'='：左操作数必须为l值



如果我尝试：

I am greeted with: error C2106: '=' : left operand must be l-value

If I try:

m_tControlMatrixTemp[0][0][0] = m_tControlMatrix[0][0][0];

它编译，但这只会交换[0]元素


我想更改结构的起始地址，以便我可以在一个上进行维护工作

下游代码可以在清理副本上工作但不知道它现在正在工作有副本。



帮助？



谢谢



：Ron

It compiles, but this only swaps the [0] elements

I want to change the start address of the structures so I can do maintenance work on one while
the code down stream can work on a cleaned up copy but not know it is now working with a copy.

Help?

Thanks

:Ron

推荐答案

如果你想对你的（相对较大的）数组使用这个技巧，你想将结构编码为：

If you want to use this trick with your (relatively large) arrays you want to code the struct as:

typedef struct {
    int x[128][5][9];
} My3Darr;

我认为这可以回答你的问题，但这个解决方案会移动相当大的内存。



更好的方法是使用指向结构的指针并交换指针。 [留给学生练习。]

I think this answers your question but this solution will move fairly large amounts of memory around.

A better way to do it is to use pointers to the structs and exchange the pointers. ["left as an exercise for the student."]

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