我无法选择图片框来绘制它们之间的界限 [英] I can not select pictureboxes to draw line between them

问题描述

在我的程序中，我有一个列表的 picturebox ，并且在程序中我按下一个新按钮<将创建code> picturebox 。但是我希望通过 MouseDown 和 MouseUp 在两个选定的图片框之间绘制2行，但不会绘制任何行。 />
这是我的代码：

In my program I have a List of picturebox and during the program when I push a button a new picturebox will be created. But I want to draw 2 lines between two selected pictureboxes by MouseDown and MouseUp but no line will be drawn.
Here is my code:

public partial class Form1 : Form
    {
        int x1, y1, x2, y2, x3, y3, x4, y4;
        List<PictureBox> pics = new List<PictureBox>();
        PictureBox thisPB;
        int i = 0;
        int j;
        void drawlines(int x1, int y1, int x2, int y2)
        {
            Graphics g = this.CreateGraphics();
            Pen p = new Pen(Color.Black,2);
            g.DrawLine(p, x1, y1, x1, y2);
            g.DrawLine(p, x1, y2, x2, y2);
            g.Dispose();
        }
        private void button1_Click(object sender, EventArgs e)
        {
            pics.Add(new PictureBox());
            pics[i].Name = "pic" + i.ToString();
            pics[i].Left = 200 * i;
            pics[i].Top = 100 * i;
            pics[i].Height = 100;
            pics[i].Width = 100;
            pics[i].SizeMode = PictureBoxSizeMode.StretchImage;
            pics[i].Image = (Image)Properties.Resources.Tulips;
            //pics[i].MouseMove += new MouseEventHandler(pic_MouseMove);
            pics[i].MouseDown += new MouseEventHandler(pic_MouseDown);
            pics[i].MouseUp+=new MouseEventHandler(pic_MouseUp);
            this.Controls.Add(pics[i]);
            i++;
        }

        void pic_MouseMove(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                PictureBox thisPB = (PictureBox)sender;
                thisPB.Left = e.X;
                thisPB.Top = e.Y;
            }
        }

        void pic_MouseDown(object sender, MouseEventArgs e) 
        {
            x3 = e.X;
            y3 = e.Y;
            //PictureBox thisPB = pics.Find(p => p.Name == pics[pics.IndexOf(p)].Name);
            thisPB = (PictureBox)sender;
            x1 = (thisPB.Right - thisPB.Left) / 2;
            y1 = (thisPB.Top - thisPB.Bottom) / 2;
        }

        void pic_MouseUp(object sender, MouseEventArgs e)
        {
            x4 = e.X;
            y4 = e.Y;
            thisPB = (PictureBox)sender;
            //PictureBox thisPB = pics.Find(p => p.Name == pics[pics.IndexOf(p)].Name);
            //if (x4 < thisPB.Right)
            x2 = (thisPB.Right - thisPB.Left) / 2;
            y2 = (thisPB.Top - thisPB.Bottom) / 2;
            
            drawlines(x1, y1, x4, y4);
        }
}

如何选择要绘制的图片？

How can I choose a picture to be selected for drawing line?

推荐答案

很多不同的人一次又一次地达成同样的想法真是太棒了。我非常确定：这是可能的，但这是一个真正的死胡同，没有任何实际意义。图片框对你没有任何帮助。



请看我过去的答案： mdi子窗体之间的绘制线 [ ^ ]。



不做感觉？



请参阅这些答案：

捕获面板上的图纸 [ ^ ]，

什么样的俏皮方法是Paint？ （DataGridViewImageCell.Paint（...）） [ ^ ]，

如何加速我的vb.net应用程序？ [ ^ ]，

如何从旧图纸中清除面板 [ ^ ]，

用C＃绘制一个矩形 [ ^ ]，

在图片框中附加图片 [ ^ ]。



而且，对于更远程的替代品，还要考虑WPF：

连接不同的控件 [ ^ ]（再次，询问者出现了想要连接控件），

C＃或VB.NET中的CorelDraw或Inkscape等矢量图形软件[ ^ ]，

架构图提示 [ ^ ]。



祝你好运，

-SA

It's wonderful how many different people come to the same idea again and again. I'm pretty much sure: this is possible, but this is a really a dead-end approach, making no practical sense. Picture boxes won't help you at all.

Please see my past answer: Drawing Lines between mdi child forms[^].

Doesn't it make sense?

Please see also these answers:
capture the drawing on a panel[^],
What kind of playful method is Paint? (DataGridViewImageCell.Paint(...))[^],
How to speed up my vb.net application?[^],
How do I clear a panel from old drawing[^],
draw a rectangle in C#[^],
Append a picture within picturebox[^].

And, for more remote alternative, also consider WPF:
Connect different controls[^] (again, the inquirer came up with the idea to connect controls),
Vector graphics software like CorelDraw or Inkscape in C# or VB.NET[^],
Architecture diagram tips[^].

Good luck,

—SA

除了一个小细节之外，您的代码似乎工作正常：图片框的坐标被错误计算。有一个简单的解决方案：

x1或x2 = pic.Left;

y1或y2 = pic.Top;

Your code seems to be working fine except for one small detail: the coordinates of the picturebox are wrongly calculated. There is a simple solution for that:
x1 or x2 = pic.Left;
y1 or y2 = pic.Top;

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